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3 years ago

What is the area of a rectangle of 5/9 m in length and 7/8 m in width

Mathematics

1 answer:

Andru [333]3 years ago

6 0

Answer:

35/72 $m^2$

Step-by-step explanation:

Rectangle Formula: $l*w=Area$

Switch the variables with the numbers given:

$\frac{5}{9} *\frac{7}{8} =Area$

Multiply the top and bottom:

5*7 = 35

9*8 = 72

35/72 = Area

You might be interested in

Factorise -75ab² - 15ac

Verdich [7]

Answer:

1) -15·a·(5·b² + c)

2) h < 4

3) 4·x² - 9

4) 1792

5) 156°

6) 2t cm

7) 2·a·m·(2·m - 3)

8) 10 cm

9) 0.00051

10) #47,250

11) -10·p·q

12) 1.35 × 10⁻⁴

13) 320°

14) 20 cm

15) 12·x²·y²

16) 6.36 × 10⁵

17) 4 cm

18) 225°

19) 1034 cm²

20) 29

Step-by-step explanation:

1) The given expression is -75·a·b - 15·a·c

Which can be expressed as -15·a·(5·b² + c)

2) The height, h < 2 × 12/6 = 4

h < 4

3) (2·x - 3)·(2·x + 3) = 4·x² - 9

4) The selling price = 1.12 × 200 × 8 = 1792

5) The interior angle of a polygon is given by the relation;

(n - 2)×180/n for 15, we get;

(15 - 2)×180/15 = 156°

6) 2t cm

7) 4·a·m² - 6·a·m = 2·a·m·(2·m - 3)

8) Slant height = √(8² + 6²) = 10 cm

9) 51 × 10⁻⁵ = 0.00051

10) Cash price = #54,000 × (1 - 0.125) = #47,250

11) -40·p·q÷(-2)² = -10·p·q

12) 0.003 × 0.045 = 1.35 × 10⁻⁴

13) N40°W = 320°

14) The base diameter of the cylinder = √(4 × (700×π cm³/7)/π) = 20 cm

15) The LCM of 2·x²·y, 3·x·y² is 12·x²·y²

16) 636,000 = 6.36 × 10⁵

17) 1/3·π·r²·h₁ = π·r²·h₂

h₂/h₁ = 1/3·π·r²/( π·r²) = 1/3

h₂/12 = 1/3

h₂ = 12/3 = 4 cm, the height of the cylinder = 4 cm

18) The angle = 180 + 45 = 225°

19) The total surface area = 22/7×14²/4 + 22/7 ×14 × 20 = 1034 cm²

20) The number is 58/2 = 29.

4 0

3 years ago

A line includes the points (4,1) and (8, 2). What is its equation in slope-intercept form?

Alisiya [41]

Answer:

$y = \frac{1}{4} x$

Step-by-step explanation:

1) First, find the slope of the equation. Use the slope formula $m= \frac{y_2-y_1}{x_2-x_1}$ . Substitute the x and y values of the given points into the formula and solve:

$m = \frac{(2)-(1)}{(8)-(4)} \\m = \frac{2-1}{8-4}\\m = \frac{1}{4}$

Thus, the slope is $\frac{1}{4}$ .

2) Now, use the point-slope formula $y-y_1 = m (x-x_1)$ to write the equation in point-slope form (from there we can convert it to slope-intercept). Substitute values for $m$ , $x_1$ , and $y_1$ .

Since $m$ represents the slope, substitute $\frac{1}{4}$ for it. Since $x_1$ and $y_1$ represent the x and y values of one point the line intersects, choose any of the given points (it doesn't matter which one, the end result will be the same) and substitute its x and y values into the formula as well. (I chose (4,1), as seen below.) Then, isolate y to put the equation in slope-intercept form and find the answer.

$y-(1) = \frac{1}{4} (x-4)\\y-1 = \frac{1}{4} x-1\\y = \frac{1}{4} x+0\\y=\frac{1}{4}x$

5 0

2 years ago

How do you solve equation with like terms if it has a fraction

larisa86 [58]

Answer:Solve equations by clearing the Denominators Find the least common denominator of all the fractions in the equation. Multiply both sides of the equation by that LCD. This clears the fractions.

Step-by-step explanation:Solve equations by clearing the Denominators Find the least common denominator of all the fractions in the equation. Multiply both sides of the equation by that LCD. This clears the fractions.

3 0

2 years ago

A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean

elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}$ ). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0

3 years ago

Is 14/950 more or less than 1/2 and why!

qwelly [4]

Well because 14 is nowhere near half of 950 (which is 475), 1/2 is bigger. I hope this helped.

3 0

3 years ago