Answer:
$2076.30
Step-by-step explanation:
In the n-th year, the rent will be ...
an = a1·r^(n-1) . . . . . . . . . r is the year on year ratio: 1+rate of increase
an = 1100·(1.095^(n-1))
Then the rent in the 8th year is ...
a8 = 1100·(1.095^(8-1)) ≈ 2076.30
The rent in the 8th year would be $2076.30.
Answer:
27,600
Step-by-step explanation:
We use the following formula:-
Number of permutations of r from n
= nPr
= n! / (n-r)!
I am assuming you don't allow repeated letters in the 4 letter codes.
Take S as the first letter. Then we have 3 letters extra out of 25 letters.
Using the above formula the possible ways of doing this is
25! / (25 - 3)!
25! / 22!
= 25*24*23
= 13800.
The same number is obtained if the first letter is a T.
So the answer is 2*13800
= 27,600
You want to figure out what the variables equal to, all of these are parallelograms meaning opposite sides and angles are equal to each other.
In question 1 start with 3x+10=43, this means that 3x is 10 less than 43 which is 33, 33 divided by 3 is 11 meaning x=11.
Same thing can be done with the sides 124=4(4y-1), start by getting rid of the parentheses with multiplication to get 124=16y-4, this means that 16y is 4 more than 124, so how many times does 16 go into 128? 8 times, so x=11 and y=8
Question 2 can be solved because opposite angles are the same in a parallelogram, so u=66 degrees
You can find the sum of the interial angles with the formula 180(n-2) where n is the number of sides the shape has, a 4 sided shape has a sum of 360 degrees, so if we already have 2 angles that add up to a total of 132 degrees and there are only 2 angles left and both of those 2 angles have to be the same value then it’s as simple as dividing the remainder in half, 360-132=228 so the other 2 angles would each be 114, 114 divided into 3 parts is 38 so u=66 and v=38
Question 3 and 4 can be solved using the same rules used in question 1 and 2, just set the opposite sides equal to each other
