All categories

3 years ago

What are the defects of mendeleev's periodic table

Chemistry

1 answer:

Elena-2011 [213]3 years ago

7 0

Answer:

1 Anomalous Pairs. The rest of the pairs of elements don't follow the follow Mendeleev's Principles . they are :

2Grouping of chemically dissimilar elements.

3Position of Isotopes.

4Electronic arrangement.

5Separation of chemically similar elements.

6The position of hydrogen.

You might be interested in

How many moles are in 40.0g of CO2

34kurt

Answer:0.90889467046888

Explanation:

7 0

3 years ago

Read 2 more answers

Who made the periodic table

TEA [102]

Answer:

Dmitri Mendeleev

Explanation:

idk

8 0

3 years ago

Read 2 more answers

Explain how materials are classified on the basis of electrical conductivity. Give two uses of these materials in day to day lif

vitfil [10]

Answer: On the basis of electrical conductivity, materials are classified as conductors, semi-conductors and non-conductors. Conductors : Substances through which electricity can easily pass through are known as conductors. ... For example, glass, wood are non-conductors. Wood is used to make tables, desks etc.

3 0

3 years ago

A substance has a high melting point and conducts electricity in the liquid phase The is substance is

posledela

Answer:

oxygen

Explanation:

3 0

4 years ago

When the volume of a gas is

Montano1993 [528]

Answer:

$\boxed {\boxed {\sf 232.9 \textdegree C}}$

Explanation:

This question asks us to find the temperature change given a volume change. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula is:

$\frac {V_1}{T_1}= \frac{V_2}{T_2}$

The volume of the gas starts at 250 milliliters and the temperature is 137 °C.

$\frac{250 \ mL}{137 \textdegree C}= \frac{V_2}{T_2}$

The volume of the gas is increased to 425 milliliters, but the temperature is unknown.

$\frac{250 \ mL}{137 \textdegree C}= \frac{425 \ mL}{T_2}$

We are solving for the new temperature, so we must isolate the variable T₂. First, cross multiply. Multiply the first numerator and second denominator, then multiply the first denominator and second numerator.

$250 \ mL * T_2 = 137 \textdegree C * 425 \ mL$