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mina [271]
2 years ago
7

Volume occupied 3.52x10^32 moluchlesof Mathane (CH4)1) At STP​

Chemistry
1 answer:
Naddika [18.5K]2 years ago
6 0

Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

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HCl + NaOH mc004-1.jpg NaCl + H2O Which substances are the reactants?
LiRa [457]
It depends on where your yields sign is, but usually it's the elements/ compounds in the front. In this case, HCL and NaOH
7 0
3 years ago
What are the four points of food safety?​
KatRina [158]

The four steps of food safety are:

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7 0
3 years ago
What mass of sodium chloride contains 4.59 x 10 24 formula units?
shtirl [24]
The term formula units means molecules.

Then, what you are looking for is the mass in 4.59*10^24  molecules.

The procedure involves to convert the 4.59 * 10^24 molecules into moles and use the molar mass of the sodium chloride.

1) Number of moles = 4.59 * 10^24 molecules / (6.02 * 10^23 molecules/mol) = 7.62 mol

2) Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

3) mass of NaCl = molar mass *  number of moles = 58.44 g/mol * 7.62 mol = 445.31 g of NaCl

Answer: 445.31 g of NaCl.

 
7 0
3 years ago
A 4.86-gram sample of calcium reacted completely with oxygen to form 6.80 grams of calcium oxide. This reaction is represented b
sesenic [268]
The number of mole of Ca reacted is:
4.86 g Ca/ (40.08 g/mol Ca)= 0.121 mol Ca

Because Ca reacted completely with oxygen and there is 2 mol Ca, there is 1 mol O2 reacted.

Total mass of oxygen that reacted is:
0.121 mol Ca* (1mol O2/ 2 mol Ca)* (32 g O2/ 1 mol O2)= 1.94 g O2 reacted.

Hope this would help~
8 0
3 years ago
Which compound is classified as a hydrocarbon? A) butanal B) butyne C) 2-butanol D) 2-butanone
fenix001 [56]

Answer:

butyne

Explanation:

alkane, alkene, and alkyne are all examples of hydrocarbons.

butyne = alkyne

7 0
3 years ago
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