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mina [271]
3 years ago
7

Volume occupied 3.52x10^32 moluchlesof Mathane (CH4)1) At STP​

Chemistry
1 answer:
Naddika [18.5K]3 years ago
6 0

Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

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In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 53.88 g of MgI₂ form, what is the pe
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We know the law of conservation of mass

  • It states that mass is neither formed nor destroyed in any chemical reaction.
  • Mass of reactants=Mass of products.

Here

  • Mg and I_2 are reactants
  • MgI_2 is product with some yield.
  • Mass of reactants=10+60.0=70.0g
  • Mass of MgI_2=53.88g
  • Mass of yield=Product-MgI_2=70-53.88=16.12g

Lets find the percentage

\\ \tt\hookrightarrow \dfrac{Mass\:of\:yield}{Total\:mass}\times 100

\\ \tt\hookrightarrow \dfrac{16.12}{70}\times 100

\\ \tt\hookrightarrow 0.23028(010)=23.028\%

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If you have 1kg of carbon and 1 kg of gold, they will weigh the same.
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What is the molarity of 0.26 mol of H2SO4 dissolved in 0.3 L of solution? *
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Answer:

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