Answer:
10.01 cm
Explanation:
Given that,
The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.
The average propagation speed for sound in body tissue is 1540 m/s.
We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,

or
d = 10.01 cm
So, the reflection will occur at 10.01 cm.
Answer: Impulse = 20 Ns
Explanation:
Impulse is the product of force and time
Also impulse = momentum
Where momentum is the product of mass and velocity.
Given that
M = 2kg
V = 10 m/s
Impulse = MV = 2 × 10 = 20 Ns
Nitrogen and carbon dioxide