Light carries away the energy. At a room temperature they are at their lowest energy
<span> The right to form a militia and to keep and bear arms.
</span><span>
Powers not given to the federal government by the Constitution belong to the states or the people.</span><span>
Freedom of religion, freedom of speech and the press, the right to assemble, the right to petition government.
</span>
Complete Question
The complete question is shown on the first uploaded image
Answer:
The strain experienced by the specimen is 0.00116 which is option A
Explanation:
The explanation is shown on the second uploaded image
Answer:
76.66V
Explanation:
Accorging to law of conservation of energy:
}
Since the protons are released from rest, the initial kinetic energy is zero and the electric potencial energy is given by: 
Now from
, we have:

Recall that
, replacing:

Rewriting (1) for
:

Now, equaling (2) and (3):

Finally, rewriting for 
