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Vesnalui [34]
2 years ago
7

A certain amount of gas at 25°C and at a pressure of 0.800 atm is contained in a glass vessel. Suppose that the vessel can withs

tand a pressure of 2.00 atm. What is the maximum temperature in Kelvin that the gas can have without bursting the vessel?
a. 745 K
b. 62.5 K
c. 298 K
d. 760 K ​
Chemistry
1 answer:
Korvikt [17]2 years ago
6 0

The maximum temperature : a. 745 K

<h3>Further explanation</h3>

Given

Gas at 25°C(298 K) and at a pressure of 0.800 atm

Final pressure = 2 atm

Required

Final temperature

Solution

Gay Lussac's Law  

When the volume is not changed, the gas pressure in the vessel is proportional to its absolute temperature  

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

Input the value :

T₂=(P₂T₁)/P₁

T₂=(2 atm x 298 K)/0.8 atm

T₂ = 745 K = 472 °C

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dmitriy555 [2]

<u>Answer:</u> The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

<u>Explanation:</u>

There are 4 quantum numbers:

  • Principal Quantum number (n) specifies the energy of the electron in a shell.
  • Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
  • Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
  • Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of +\frac{1}{2} or -\frac{1}{2}

Berylium (Be) is the 4th element of periodic table having electronic configuration of 1s^22s^2

  • <u>For electrons in 1s-orbital, the quantum numbers can be:</u>

For first electron:

n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}

For second electron:

n=1\\l=0\\m=0\\s=-\frac{1}{2}

  • <u>For electrons in 2s-orbital, the quantum numbers can be:</u>

For first electron:

n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}

For second electron:

n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

4 0
3 years ago
Examine the scenario.
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3 years ago
What role does the wire play in voltaic cell?
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<h3><u>Answer;</u></h3>

a) It allows electrons to flow from the anode to the cathode.

<h3><u>Explanation</u>;</h3>
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3 years ago
A compound with a molar mass of 60g/mol is 40.4% carbon, 6.7% hydrogen and 53.3% oxygen (by mass). determine the emperical and m
Fittoniya [83]

<span>A compound is found to be 40.0% carbon, 6.7% hydrogen and 53.5% oxygen. Its molecular mass is 60. g/mol. 
</span>Q1)
Empirical formula is the simplest ratio of whole numbers of components making up a compound.
the percentages have been given, therefore we can calculate for 100 g of the compound.

                                C                            H                        O
Mass in 100 g      40.0 g                       6.7 g                   53.5 g
Molar mass            12 g/mol                1 g/mol                 16 g/mol
Number of moles   40.0/12= 3.33         6.7/1 = 6.7          53.5/16 = 3.34
Divide by the least number of moles  
                             3.33/3.33 = 1           6.7/3.33 = 2.01   3.34/3.33 = 1.00
after rounding off
C - 1 
H - 2
O - 1

Empirical formula - CH₂O

Q2)
Molecular formula is the actual number of components making up the compound.
To find the number of empirical units we have to find the mass of one empirical unit.
Mass of one empirical unit = CH₂O - 12 + (1x2) + 16 = 30 g
Mass of one mole of compound = 60 g
Number of empirical units = 60 g / 30 g = 2
Therefore molecular formula - 2(CH₂O) 
 Molecular formula - C₂H₄O₂
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3 years ago
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