Question

Part B Identify the sets of quantum numbers that describe all the electrons in the ground state of a neutral beryllium atom, Be. Each set is ordered (n, l, me, ms). Drag the appropriate items to their respective bins. View Available Hint(s) Reset Help 2,0,0,1/2 2,1,-1,1/2 2,1,0,1/2 1,0,0,-1/2 2,1,-1,-12 1,0,0,1/2 2,1,0,-1/2 2,0,0,-1/2 Electrons in Be Electrons not in Be Submit​

Answer 1

Answer: The set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)

Explanation:

There are 4 quantum numbers:

• Principal Quantum number (n) specifies the energy of the electron in a shell.
• Azimuthal Quantum number (l) specifies the shape of an orbital. The value of it lies in the range of 0 to (n-1)
• Magnetic Quantum number (m) specifies the orientation of the orbital in space. The value of it lies in the range of -l to +l
• Spin Quantum number (s) specifies the spin of an electron in an orbital. It can either have a value of $+\frac{1}{2}$ or $-\frac{1}{2}$

Berylium (Be) is the 4th element of periodic table having electronic configuration of $1s^22s^2$

• For electrons in 1s-orbital, the quantum numbers can be:

For first electron:

$n=1\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=1\\l=0\\m=0\\s=-\frac{1}{2}$

• For electrons in 2s-orbital, the quantum numbers can be:

For first electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=+\frac{1}{2}$

For second electron:

$n=2\\l=0\text{ (for s-subshell)}\\m=0\\s=-\frac{1}{2}$

Hence, the set of quantum numbers for the electrons in Be atom are (2, 1, -1, 1/2), (1, 0, 0, 1/2), (1, 0, 0, -1/2) and (2, 0, 0, -1/2)