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UNO [17]
3 years ago
7

A small rock is thrown vertically upward with a speed of 21.0 m/s from the edge of the roof of a 35.0-m-tall building. The rock

doesn't hit the building on its way back down and lands in the street below. Ignore air resistance.(a) What is the speed of the rock just before it hits the street?(b) How much time elapses from when the rock is thrown until it hits the street?
Physics
1 answer:
klasskru [66]3 years ago
6 0

Answer:

a) Vf = 33.78m/s

b) t = 5.478s

Explanation:

We can calculate final speed using:

Vf^{2}=Vo^{2}-2*g*\Delta Y

where Vo = 21m/s;  g = 10m/s2;   ΔY = -35m

Vf = 33.78m/s

Now, having final speed, we can calculate the amount of time elapsed:

Vf = Vo - g * t    where Vf = -33.78m/s;   Vo = 21m/s;   g = 10m/s2

t = 5.478s

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levacccp [35]

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D, both A and B

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The primary unit is Volt, represented as V. Due to the fact that there can be a much higher reading, or an even much more smaller one, comes the need for variants of the same unit.

10^-3 is called milli and represented as m

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10^-6 is called micro and represented as µ

10^6 is called mega and represented as M

and even much higher variants of up to 10^12 and 10^-12

As we can see from the aforementioned example, 10^-3 is milli and represented as m

And our question gave us the unit in mV, which stands for millivolts.

Also, if we look at option B, it states, 2.168 volts. This 2.168 volts is also the same thing as A. Take a look at it this way, I said mV is 10^-3, right?

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