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UNO [17]
3 years ago
7

A small rock is thrown vertically upward with a speed of 21.0 m/s from the edge of the roof of a 35.0-m-tall building. The rock

doesn't hit the building on its way back down and lands in the street below. Ignore air resistance.(a) What is the speed of the rock just before it hits the street?(b) How much time elapses from when the rock is thrown until it hits the street?
Physics
1 answer:
klasskru [66]3 years ago
6 0

Answer:

a) Vf = 33.78m/s

b) t = 5.478s

Explanation:

We can calculate final speed using:

Vf^{2}=Vo^{2}-2*g*\Delta Y

where Vo = 21m/s;  g = 10m/s2;   ΔY = -35m

Vf = 33.78m/s

Now, having final speed, we can calculate the amount of time elapsed:

Vf = Vo - g * t    where Vf = -33.78m/s;   Vo = 21m/s;   g = 10m/s2

t = 5.478s

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Distance= speed x time

distance = 2.6 m/s x 120s

distance= 312 meters

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the force shown in figure 7-15 moves an object from x=0 to x=0.75 m. How much work is done by the force?
Phantasy [73]
Work is force multiplied by the distance the force moves the object
6 0
3 years ago
Which dog has the most kinetic energy
Blababa [14]
The formula to find the kinetic energy is:

Ek= 1/2 × m × v^2

1. Ek= 1/2×15×3^2
= 67.5 J

2.Ek= 1/2×8×4^2
=64 J

3.Ek= 1/2×12×5^2
= 150 J

4.Ek= 1/2×10×6^2
= 180 J

So the fourth dog has the most kinetic energy.
4 0
3 years ago
The combination of all forces that act on an object are (2 points)
qaws [65]

Answer:

A) The net force

Explanation:

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5 0
3 years ago
A vector A has a magnitude of 5 units and points in the −y-direction, while a vector B has triple the magnitude of A and points
Harman [31]

Answer:

A+B; 5√5 units, 341.57°

A-B; 5√5 units, 198.43°

B-A; 5√5 units, 18.43°

Explanation:

Given A = 5 units

By vector notation and the axis of A, it is represented as -5j

B = 3 × 5 = 15 units

Using the vector notations and the axis, B is +15i. The following vectors ate taking as the coordinates of A and B

(a) A + B = -5j + 15i

A+B = 15i -5j

|A+B| = √(15)²+(5)²

= 5√5 units

∆ = arctan(5/15) = 18.43°

The angle ∆ is generally used in the diagrams

∆= 18.43°

The direction of A+B is 341.57° based in the condition given (see attachment for diagrams

(b) A - B = -5j -15i

A-B = -15i -5j

|A-B|= √(15)²+(-5)²

|A-B| = √125

|A-B| = 5√5 units

The direction is 180+18.43°= 198.43°

See attachment for diagrams

(c) B-A = 15i -( -5j) = 15i + 5j

|B-A| = 5√5 units

The direction is 18.43°

See attachment for diagram

5 0
3 years ago
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