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UNO [17]
3 years ago
7

A small rock is thrown vertically upward with a speed of 21.0 m/s from the edge of the roof of a 35.0-m-tall building. The rock

doesn't hit the building on its way back down and lands in the street below. Ignore air resistance.(a) What is the speed of the rock just before it hits the street?(b) How much time elapses from when the rock is thrown until it hits the street?
Physics
1 answer:
klasskru [66]3 years ago
6 0

Answer:

a) Vf = 33.78m/s

b) t = 5.478s

Explanation:

We can calculate final speed using:

Vf^{2}=Vo^{2}-2*g*\Delta Y

where Vo = 21m/s;  g = 10m/s2;   ΔY = -35m

Vf = 33.78m/s

Now, having final speed, we can calculate the amount of time elapsed:

Vf = Vo - g * t    where Vf = -33.78m/s;   Vo = 21m/s;   g = 10m/s2

t = 5.478s

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