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3 years ago

What type of reaction does this equation represent? 2I4O9(s) → 4I2(s) + 9O2(g)

Chemistry

1 answer:

Tju [1.3M]3 years ago

4 0

Answer:

2I4O9_4I +9O

Explanation:

Complex compound (

) is broken down to form

and

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Sodium hydroxide +ammonium sulphate ==>ammonia+sodium sulphate+water coefficients <br>

zysi [14]

Answer:

Below

Explanation:

Balanced equation: 2NaOH + (NH4)2SO4 = 2NH3 + 2H2O + Na2SO4

The coefficients would be 2

8 0

2 years ago

Use the solubility curve above to answer the following: If I add 130 g of potassium iodide to 100 g of water at 10°C, how would

zhenek [66]

<span>solution of KI becomes saturated at 10 degrees when around 135-138g KI are added to 100 g of water, so it should be still unsaturated, A. unsaturated (although it is very close to saturation)</span>

7 0

3 years ago

A device that sends electrical impulses to the heart to correct an irregular

IgorC [24]

A. A pacemaker

Hope this helps!

6 0

2 years ago

Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:

rusak2 [61]

Answer:

60.42% is the percent yield of the reaction.

Explanation:

Moles of methane gas at 734 Torr and a temperature of 25 °C.

Volume of methane gas = V = 26.0 L

Pressure of the methane gas = P = 734 Torr = 0.9542 atm

Temperature of the methane gas = T = 25 °C = 298.15 K

Moles of methane gas = n

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.9542 atm\times 26.0L}{0.0821 atm L/mol K\times 298.15 K}=1.0135 mol$

Moles of water vapors at 700 Torr and a temperature of 125 °C.

Volume of water vapor = V' = 23.0 L

Pressure of water vapor = P' = 700 Torr = 0.9100 atm

Temperature of water vapor = T' = 125 °C = 398.15 K

Moles of water vapor gas = n'

$P'V'=n'RT'$

$n'=\frac{PV}{RT}=\frac{0.9100 atm\times 23.0L}{0.0821 atm L/mol K\times 398.15 K}=0.6402 mol$

$CH_4(g)+H_2O(g)\rightarrow CO(g)+3H_2(g)$

According to reaction , 1 mol of methane reacts with 1 mol of water vapor. As we can see that moles of water vapors are in lessor amount which means it is a limiting reagent and formation of hydrogen gas will depend upon moles of water vapors.

According to reaction 1 mol of water vapor gives 3 moles of hydrogen gas.

Then 0.6402 moles of water vapor will give:

$\frac{3}{1}\times 0.6402 mol=1.9208 mol$ of hydrogen gas