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3 years ago

What type of reaction does this equation represent? 2I4O9(s) → 4I2(s) + 9O2(g)

Chemistry

1 answer:

Tju [1.3M]3 years ago

4 0

Answer:

2I4O9_4I +9O

Explanation:

Complex compound (

) is broken down to form

and

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Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.

djverab [1.8K]

Answer:

2.445 g

Explanation:

Step 1: Given and required data

Energy in the form of heat required to boil the water (Q): 5525 J

Latent heat of vaporization of water (∆H°vap): 2260 J/g

Mass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

4 0

2 years ago

In the second step of this reaction, isocyanic acid reacts to form melamine and carbon dioxide: HNCO(l)→C3N3(NH2)3(l)+CO2(g) Bal

kykrilka [37]

Answer:

The coefficients are 6, 1, 3

Explanation:

HNCO →C3N3(NH2)3 + CO2

From the above equation, there are a total of 6 atoms of nitrogen on the right side and 1atom on the left. It can be balance by putting 6 in front of HNCO as shown below:

6HNCO → C3N3(NH2)3 + CO2

Now there are 6 atoms of carbon on the left side and 4 atoms on the right side. It can be balance by putting 3 in front of CO2 as shown below:

6HNCO → C3N3(NH2)3 + 3CO2

Now the equation is balanced as the numbers of atoms of the different elements on both sides of the equation are the same.

The coefficients are 6, 1, 3

8 0

3 years ago

When you connect your evidence to your claim you are using your

trapecia [35]

Answer:

2. reasoning

Explanation:

PLS GIVE BRAINLIEST

3 0

2 years ago

A solution is made containing 4.6 g of sodium chloride per 250g of water.

lozanna [386]

Answer:

$\large \boxed{1.81 \, \%}$

Explanation:

$\text{Mass percent} = \dfrac{\text{mass of solute} }{\text{mass of solution}} \times 100 \, \%$

Data:

Mass of NaCl = 4.6 g

Mass of water = 250 g

Calculations:

Mass of solution = mass of NaCl + mass of water = 4.6 g + 250 g = 254.6 g.

$\text{\% m/m} = \dfrac{\text{4.6 g} }{\text{254.6 g}} \times 100 \, \% = \mathbf{1.81 \, \%}\\\\\text{The percent by mass of NaCl is $\large \boxed{\mathbf{1.81 \, \%}}$}$

3 0

3 years ago

zn (s) 2 hcl (aq) -----> zncl2 (aq) h2(g) if 520 ml of h2 is collected over water at 28oc and the atmospheric pressure is 1.0

nadya68 [22]

The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.

Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.

We recognise that

h * 2 = PT - P * h * 20 = 1atm - 0.037atm

= 0.963 atm

1 * h * 2 = Ph * 2V / R * T

= 0.963 atm x 0.520 L / 0.0821 L atm/

molK * 301

= 0.02 mol h2

= 0.02molZn

So 0.02 mol Zn x 65.39 g/mol

= 1.33 g Zn