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PolarNik [594]
11 months ago
6

If cells did not work together what would happen to the organisms

Chemistry
1 answer:
arlik [135]11 months ago
5 0

Surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

<h3>Living organisms </h3>

Living organisms; be it plants or animals are any organic or living system composed of cells and function as an individual entity.

  • All living organisms share a number of key characteristics or functions such as movement, respiration, homeostasis, reproduction, growth, evolution, competition and others.

  • Animals and plants also posess systems such as the digestive, skeletal, transport, nervous, excretory, respiratory and reproductive system.

  • Living organisms are also taxonomically classified as either unicellular microorganisms or multicellular plants and animals

So therefore, surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

Learn more about living organisms:

brainly.com/question/17259533

#SPJ1

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Which shows the formula for an organic acid?
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Answer:

A

Explanation:

CH3CH2COOH- Propanoic Acid

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is the atomic mass of chlorine represented by the mass of the most common naturally occurring isotope in chlorine?
IrinaVladis [17]
Combine the number of its Protons and Neutrons and you will have its atomic mass.
8 0
3 years ago
A lead mass is heated and placed in a foam cup calorimeter containing 40.0 mL of water at 17.0°C. The water reaches a temperatur
lbvjy [14]

Answer: 502 Joules

Explanation:

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 40.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{40.0mL}\\\\\text{Mass of water}=(1g/mL\times 40.0mL)=40.0g

When metal is dipped in water, the amount of heat released by lead will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

q=m\times c\times \Delta T

q = heat absorbed by water

m = mass of water = 40.0 g

T_{final} = final temperature of water = 20.0°C

T_{initial = initial temperature of water = 17.0°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

q=40.0\times 4.186\times (20.0-17.0)]

q=502J

Hence, the joules of heat were re-leased by the lead is 502

5 0
3 years ago
Determine the number of molecules in a 100. gram sample of CCl4
enyata [817]
100. g CCl4* (1 mol CCl4/ 153.8 g CCl4)* (6.02*10^23 CCl4 molecules/ 1 mol CCl4)= 3.91*10^23 CCl4 molecules.
(Note that the units cancel out so you get the answer)

Hope this helps~
8 0
3 years ago
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