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PolarNik [594]
1 year ago
6

If cells did not work together what would happen to the organisms

Chemistry
1 answer:
arlik [135]1 year ago
5 0

Surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

<h3>Living organisms </h3>

Living organisms; be it plants or animals are any organic or living system composed of cells and function as an individual entity.

  • All living organisms share a number of key characteristics or functions such as movement, respiration, homeostasis, reproduction, growth, evolution, competition and others.

  • Animals and plants also posess systems such as the digestive, skeletal, transport, nervous, excretory, respiratory and reproductive system.

  • Living organisms are also taxonomically classified as either unicellular microorganisms or multicellular plants and animals

So therefore, surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

Learn more about living organisms:

brainly.com/question/17259533

#SPJ1

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What are the similarities between nucleotides?
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Nucleotides are organic molecules consisting of a nucleoside and a phosphate.

They serve as monomeric units of the nucleic acid polymers – deoxyribonucleic acid (DNA) and ribonucleic acid (RNA), both of which are essential biomolecules within all life-forms on Earth. Nucleotides are obtained in the diet and are also synthesized from common nutrients by the liver.

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6 0
1 year ago
The temperature of a 15-g sample of lead metal increases from 22 °C to 37 °C upon the addition of 29.0 J of heat. The specific h
Kryger [21]

Answer:

0.13 J/g.°C.

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by lead (Q = 29.0 J).

m is the mass of lead (m = 15.0 g).

c is the specific heat capacity of lead (c = ??? J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  37 °C - 22 °C = 15.0 °C).

∵ Q = m.c.ΔT

<em>∴ c = Q/m.ΔT </em>= (29.0 J)/(15.0 g)(15.0 °C) = <em>01288 J/g.°C ≅ 0.13 J/g.°C.</em>

3 0
4 years ago
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