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1 year ago

If cells did not work together what would happen to the organisms

1 answer:

5 0

Surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

<h3>Living organisms </h3>

Living organisms; be it plants or animals are any organic or living system composed of cells and function as an individual entity.

All living organisms share a number of key characteristics or functions such as movement, respiration, homeostasis, reproduction, growth, evolution, competition and others.

Animals and plants also posess systems such as the digestive, skeletal, transport, nervous, excretory, respiratory and reproductive system.

Living organisms are also taxonomically classified as either unicellular microorganisms or multicellular plants and animals

So therefore, surely, If cells did not work together in an organism, there won't be formation of new cells and life process would stop

Learn more about living organisms:

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You might be interested in

what does it mean when the h3o+ to x- distance doesn't change much as the first 4 to 5 water molecules are added

podryga [215]

If X is an equivalent base to H₂O
HX is an equivalent acid to H₃O⁺
HX is a stronger acid than H₃O⁺
HX is not an acid
X⁻ is a stronger base than H₂O
HX is a weaker acid than H₃O⁺
X⁻ is a weaker base than H₂O
X⁻ is not a base.

The correct response or this is
X⁻ is a stronger base than H₂O
HX is a weaker acid than H₃O⁺

7 0

3 years ago

Read 2 more answers

What is water's density at 93 ∘C? Assume a constant coefficient of volume expansion. Express your answer with the appropriate un

Ganezh [65]

Answer:

982.5 kg/m³

Explanation:

When the temperature of a fluid increases, it dilates, and because of the variation of the volume, it's density will vary too. The density can be calculated by the expression:

ρ₁ = ρ₀/(1 + β*(t₁ - t₀))

Where ρ₁ is the final density, ρ₀ the initial density, β is the constant coefficient of volume expansion, t₁ the final temperature, and t₀ the initial temperature.

At t₀ = 4°C, the water desity is ρ₀ = 1,000 kg/m³. The value of the constant for water is β = 0.0002 m³/m³ °C, so, for t₁ = 93°C

ρ₁ = 1,000/(1 + 0.0002*(93 - 4))

ρ₁ = 1,000/(1+ 0.0178)

ρ₁ = 982.5 kg/m³

3 0

3 years ago

Helium gas in a cylinder is under 1.12atm pressure at 25.0C. What will be the pressure if the temperature increases to 37.0C?

Irina18 [472]

Answer:

$p_2=1.17atm$

Explanation:

Hello!

In this case, considering that the Gay-Lussac's law allows us to relate the temperature-pressure problems as directly proportional relationships:

$\frac{p_2}{T_2} =\frac{p_1}{T_1} \\\\$

Thus, for the initial pressure and temperature in kelvins the final temperature in kelvins, we compute the final pressure as:

$p_2=\frac{p_1T_2}{T_1} \\\\p_2=\frac{1.12atm*310.15K}{298.15K}\\\\p_2=1.17atm$

Best regards!

7 0

3 years ago

At 700 K, the reaction 2SO2(g) + O2(g) <====> 2SO3(g) has the equilibrium constant Kc = 4.3 x 106. At a certain instant, f

nadya68 [22]

Answer:

The system is not in equilibrium and will evolve left to right to reach equilibrium.

Explanation:

The reaction quotient Qc is defined for a generic reaction:

aA + bB → cC + dD

$Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b} }$

where the concentrations are not those of equilibrium, but other given concentrations

Chemical Equilibrium is the state in which the direct and indirect reaction have the same speed and is represented by a constant Kc, which for a generic reaction as shown above, is defined:

$Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b} }$

where the concentrations are those of equilibrium.

This constant is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients divided by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

Comparing Qc with Kc allows to find out the status and evolution of the system:

If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.

If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

In this case:

$Q=\frac{[So_{3}] ^{2} }{[SO_{2} ]^{2}* [O_{2}] }$

$Q=\frac{10^{2} }{0.10^{2} *0.10}$

Q=100,000

100,000 < 4,300,000 (4.3*10⁶)

Q < Kc

<u><em> The system is not in equilibrium and will evolve left to right to reach equilibrium.</em></u>

3 0

3 years ago

In the following reaction 2C6H6 + 15O2 12CO2 + 6H2O how many grams of oxygen will react with 10.47 grams of benzene (C6H6)?

IRINA_888 [86]

$2 C_{6}H_{6} + 15O_{2} ----->\ \textgreater \ 12CO_{2} + 6H_{2}O


$

$mol of benzene = \frac{mass}{Mr}$
= $\frac{10.47g}{(6 * 12) (6 * 1) g/mol}$
= 0.134 mol

mol of oxygen:
ratio of $C_{6} H_{6} : O_{2}$
= 2 : 15
= 1 : 7.5

: . mol of $O_{2}$ = 0.134mol * 7.5
= 1.01 mol

Mass of Oxygen = mol * Mr
= 1.01 mol * (16*2) g/mol
= 32.22g

Note: Mr is molar mass

8 0

3 years ago