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yawa3891 [41]
4 years ago
8

How does Scientific theories differ from scientific laws

Physics
1 answer:
finlep [7]4 years ago
7 0
Hey there!

\ggg \ scientific \ laws : Scientific law's would be a law that was proven and test and examined by scientist.These laws would basically be fact's, proven that what ever they say would technically be true.

\ggg \ Scientific \ theories: These are "theories" that are made by scientist usually hypothesis to see what law would actually be true. These "theories" are of course not true, they are not quite laws, they are experiment's that could be laws, but they're theories, thing's that are technically false.

Hope this helps you!
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A car is initially moving at 35 km/h along a straight highway. To pass another car, it speeds up to 135 km/h in 10.5 seconds at
Aleks04 [339]
Acceleration = (velocity final-velocity initial)/ time
where
velocity final = 135 km/hr x 1 hr /3600 s x 1000m/1km
                     = 37.5 m/s
velocity initial = 35 km/hr x  1hr /3600 s x 1000 m/1 km
                      =  9.72 m/s
a) acceleration = 2.646 m/s^2
b) acceleration in g units  = (2.646m/s^2)/(9.8m/s^2)
                                              = 0.27 units

6 0
4 years ago
Which of the following types of waves can transmit only through matter? Select all that apply. (Hint: there are 2)
Anarel [89]
A) seismic waves
b) sound waves

sound waves are traveling vibrations of particles in media (air, water, metal, etc) so they can’t travel through empty space (vacuums) because there are no atoms or molecules to vibrate.

seismic waves are mechanical waves and require a medium for propagation, hence, they cannot travel through a vacuum.

hope this helps :)
7 0
3 years ago
An incline plane has Ф = 40.0° and μ k = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m
lesya [120]
     The block on the action of two forces, the Force of Friction and the Tangential Weight. Using the Newton's Secound Law, we have:

P_{t}-Fat=ma \\ mgsen\O-mgucos\O=ma \\ a=g(sen\O-ucos\O)
 
     Using the Velocity Hourly Equation, we get:

V=V_{o}+a\Delta t \\ \Delta t= \frac{V}{a}
 
     Uniting the equations:

\Delta t=  \frac{V}{g(sen\O-ucos\O)}
 
     Entering the unknowns:

\Delta t= \frac{V}{g(sen\O-ucos\O)} \\ \Delta t= \frac{12}{10(sen40^o-0.15cos^o)}  \\ \Delta t= \frac{12}{10(0,64-0.15x0.77)}  \\ \Delta t= \frac{12}{5.27}  \\ \boxed {\Delta t=2.28s}

Obs: Approximate results

If you notice any mistake in my english, please let me know, because i am not native.

5 0
3 years ago
If I exert a 203 N force on a 58 kg box, what will the acceleration of the box be?
Anit [1.1K]

Answer:

<h2>3.5 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

m is the mass

f is the force

From the question we have

a =  \frac{203}{58} =  \frac{7}{2}   \\

We have the final answer as

<h3>3.5 m/s²</h3>

Hope this helps you

7 0
3 years ago
An dog is transported from the earth to the moon. which measurement is the same in both places
lys-0071 [83]

The dog's length, width, height, mass, volume, density, and color are the same in both places.

4 0
3 years ago
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