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3 years ago

A characteristic necessary to give a physical object movement?

1 answer:

4 0

A characteristic necessary to give a physical object movement is called a force. From the second law of motion, wherein the mass and acceleration of an object is needed to keep it moving. And this is called the force of an object.

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A charge of +1.4×10^6 coulombs moves from point a to b. What is the potential difference between the two points if the work done

Rama09 [41]

The potential difference between the two points if the work done on the charge is +3.4×10^7 joules would be A. 10volts.

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3 years ago

When a wave slows down it...

tangare [24]

<span>a. bends away from the normal</span>

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3 years ago

Read 2 more answers

Which of the following statements about diodes and triodes is correct

nata0808 [166]

There are no correct statements on your list.

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3 years ago

The energy from radiation can be used to cause the rupture of chemical bonds. A minimum energy of 242kJ/mol is required to break

iris [78.8K]

Answer:

The longest wavelength of radiation that passesses the necessary energy for breaking the Cl- Cl bond (in Cl2) is approximately 494.2 nm, which corresponds to the visible spectrum.

Explanation:

In order to answer this question we need to recall that the energy of a photon is given by:

E = hc/lambda, where

E = energy

h = Planck's constant

c = speed of light in vacuum

lambda = associated photon wavelength

In order to perform the calculations, first we need to change the units of 242kJ/mol to J. For doing this, we to divide by Avogadro's number and multiply by a 1000:

242kJ/mol = (242kJ/mol)*(1mol/6.022x10^23 particles)*(1000J/1kJ)= 4.0186x10^-19 J

Now, we simply solve for lambda and substitute the appropriate values in the energy equation:

lambda = hc/E = (6.626x10^-34 J s)*(3x10^8 m/s)/(4.0186x10^-19 J) = (1.986x10^-25 J m)/(4.0186x10^-19 J) = 4.942x10^-7 m = 494.2x10^-9 m = 494.2 nm

Therefore, the wavelength for a photon to break the Cl-Cl bond in a Cl2 molecule should be 494.2 nm at most, which corresponds to the visible spectrum (The visible spectrum includes wavelengths between 400 nm and 750 nm).

3 0

4 years ago

Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initia

earnstyle [38]

Answer:

The acceleration of rocket B is -22.24 m/s²

Explanation:

Two rockets are flying in the same direction and are side by side at the

instant their retrorockets fire

That means they started from the same point at the same time

Rocket A has an initial velocity of 5800 m/s

Rocket B has an initial velocity of 8600 m/s

After a time t both rockets are again side by side, the displacement of

each being zero

That means they are in the same position again → s = 0

The acceleration of rocket A is -15 m/s²

We need to find the acceleration for rocket B

We can find the time from the information of rocket A by using the

rule → s = u t + $\frac{1}{2}$ a t²

where s is the displacement, u is the initial velocity, a is the

acceleration, and t is the time

→ s = 0 , u = 5800 m/s , a = -15 m/s²

Substitute these values in the rule

→ 0 = 5800 t + $\frac{1}{2}$ (-15) t²

→ 0 = 5800 t - 7.5 t²

Add 7.5 t² for both sides

→ 7.5 t² = 5800 t

Divide both sides by 7.5 t

→ t = 773.3 s

The time for the both rocket to have displacement zero is 773.3 s

Now we can find the acceleration of the rocket B by using the same

rule above

→ u = 8600 m/s , t = 773.3 , s = 0

→ 0 = (8600)(773.3) + $\frac{1}{2}$ a (773.3)²

→ 0 = 6650380 + 298996.445 a

Subtract 6650380 from both sides

→ -6650380 = 298996.445 a

Divide both sides by 298996.445

→ a = -22.24 m/s²

<em>The acceleration of rocket B is -22.24 m/s²</em>

6 0

4 years ago