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Hitman42 [59]
4 years ago
9

With what speed must a ball be thrown vertically from ground level to rise to a maximum height of 41 m

Physics
1 answer:
marishachu [46]4 years ago
6 0

Answer:

The speed must a ball be thrown vertically from ground level to rise to a maximum height is 28.35 m/s.

Explanation:

Given;

maximum vertical height of the throw, H = 41 m

Apply the following kinematic equation;

V² = U² + 2gH

where;

V is the final speed with which the ball will rise to a maximum height

U is the initial speed of the ball = 0

g is acceleration due to gravity = 0

V² = U² + 2gH

V² = 0² + 2gH

V² =  2gH

V = √2gH

V = √(2 x 9.8 x 41)

V = 28.35 m/s

Therefore, the speed must a ball be thrown vertically from ground level to rise to a maximum height is 28.35 m/s.

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qaws [65]

Answer:

≅50°

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And since we're using Δx, V₀ should really be the initial velocity in the x-direction. So:

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Now luckily we are given everything we need to solve (or you found the info before posting here):

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With that we can plug the values in to get:

760=(87)(cos\theta )(13.6)+\frac{(0)(13.6^{2}) }{2}

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