2-Ethoxy-2,3-dimethylbutane reacts with concentrated aqueous HI to form two initial organic products (A and B). Further reaction
with HI produces organic product C from product B. Draw the structures of these three products.
1 answer:
Answer:
A = 2-iodo-2,3-dimethylbutane
B = Ethanol
C = Iodoethane (also called ethyl-iodide)
Explanation:
2-Ethoxy-2,3-dimethylbutane reacts with conc. HI to cleave the oxy-functional group.
On one end, ethanol is formed and on the other hand, 2-iodo-2,3-dimethylbutane is formed.
But ethanol reacts further with conc HI to give iodoethane.
Therefore,
A = 2-iodo-2,3-dimethylbutane
B = Ethanol
C = Iodoethane (also called ethyl-iodide)
This is all shown in the attached image.
Hope this Helps!!!
You might be interested in
Answer:
C.
Explanation:
Stereoisomers are molecules that have the same molecular formula and with their atoms connected in the same way but pointing in different directions.
<em>cis</em>-Pent-2-ene has formula C₅H₁₀
A. is wrong, because its formula is C₅H₁₂
B. and D. are wrong, because their formulas are C₅H₈
The only option left is C. It has formula C₅H₁₀
C. is a stereoisomer of <em>cis</em>-pent-2-ene, because atoms 1 and 4 are on opposite sides of the double bond.
Think of the C=C bond as a river.
In the <em>cis </em>isomer (top), atoms 1 and 4 are on the same side of the river (zis = zame zide).
In the <em>trans</em> isomer (bottom), atoms 1 and 4 are on opposite sides of the river (trans = across or opposite).
So, C. is a stereoisomer of cis-pent-2-ene.
