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tamaranim1 [39]
3 years ago
13

The electric force between two charged objects is 64 N. What will be the magnitude of the electric force if the distance between

these two
charges is cut in half?
Physics
1 answer:
Alexeev081 [22]3 years ago
6 0
DONT SUBMIT THE LINK. IT COULD CONTAIN BAD ACTIVITY OR COULD TAKE PERSONAL INFO!
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What is free nitrogen
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4 years ago
A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q
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Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges q_1 and q_2 separated by a distance d, the magnitude of the electrostatic force F between them is:

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q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}

and knowing the value of the Coulomb's constant:

k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}

Taking all this in consideration:

F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}

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The Newton is the SI unit for ____.<br> temperature<br> mass<br> weight<br> density
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