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vovangra [49]
3 years ago
12

Word scrumble pe grade nine EESSNTILOP

Physics
1 answer:
katrin [286]3 years ago
7 0

i dont know

Explanation:

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When a wire loop is connected to a battery, what is produced in the loop?
Vinil7 [7]

Answer:

magnetic field

Explanation:

3 0
3 years ago
Sound waves are a- Transverse b- Longitudinal c- Transverse and longitudinal
Katen [24]

Answer:

Sound waves are longitudinal in nature.

Explanation:

There are many types of waves like transverse, longitudinal, electromagnetic wave etc.

Sound waves are longitudinal in nature. In longitudinal type of wave, the medium particles moves parallel to the propagation of the wave. This type of waves move in the form of compression and rarefaction.

In compression, the particle density at a point is very less while in rarefaction, the particle density at a point is very high.

So, the correct option is (b) "longitudinal wave".

3 0
3 years ago
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The first model of the atom was developed through scientific experimentation and data analysis with water vapor and gases. obser
stellarik [79]

Answer:

The answer is C. thinking about the smallest particles of matter without experimenting.

6 0
3 years ago
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Jane described two substances which participate in photosynthesis. Substance A: Combines with water Substance B: Gaseous product
saul85 [17]
<span>I am pretty sure the correct answer is C.
It makes the most sense.
Please correct me if I'm wrong.</span>
5 0
3 years ago
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Two very large parallel metal plates, separated by 0.20 m, are connected across a 12-V source of potential. An electron is relea
Semmy [17]

Answer:

{\rm K} = 2.4\times 10^{-19}~J

Explanation:

The electric field inside a parallel plate capacitor is

E = \frac{Q}{2\epsilon_0 A}

where A is the area of one of the plates, and Q is the charge on the capacitor.

The electric force on the electron is

F = qE = \frac{qQ}{2\epsilon_0 A}

where q is the charge of the electron.

By definition the capacitance of the capacitor is given by

C = \epsilon_0\frac{A}{d} = \frac{Q}{V}\\\frac{Q}{\epsilon_0 A} = \frac{V}{d} = \frac{12}{0.20} = 60

Plugging this identity into the force equation above gives

F = \frac{qQ}{2\epsilon_0 A} = \frac{q}{2}(\frac{Q}{\epsilon_0 A}) = \frac{q}{2}60 = 30q

The work done by this force is equal to change in kinetic energy.

W = Fx = (30q)(0.05) = 1.5q = K

The charge of the electron is 1.6 \times 10^{-19}

Therefore, the kinetic energy is 2.4\times 10^{-19}

8 0
4 years ago
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