Which velocity-time graph matches the position-time graph?
2 answers:
Explanation:
In this question, a position time graph is shown. We need to find the corresponding velocity time graph.
In position time graph, till 1 second the object is in uniform motion and reaches a distance of 30 meters. Then the object is at till 3 seconds. After 3 seconds, the object again reaches a distance of 40 meters uniformly.
Corresponding velocity-time graph is shown in figure (3). The object is moving initially with a speed of 30 m/s. After 1 second, it comes to rest till 3 seconds then it again moves. So, the correct option is (c). Hence, this is the required solution.
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Answer:
stress = 16.9 MPa
Explanation:
The stress in the cable can be calculated as:
Where F is the force and A is the area. So, the area can be calculated as:
Where r is the radius. Since the radius is half the diameter, the radius is 4.0 mm and the area will be equal to:
Then, replacing the force F by 850 N, and A by 50.24 mm², we get that the stress is equal to:
Therefore, the answer is 16.9 MPa