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pav-90 [236]
3 years ago
13

Which of the following statements is true in the case of a collision?

Physics
1 answer:
cluponka [151]3 years ago
3 0

Answer: D

Reduced impact time will increase the impact force

Explanation: Collision occurs when two or more bodies collide and exert forces on each other within a short time.

If a body of mass M moving with a velocity V collide with another body, the kinetic energy of the body is equal to the work done by the body.

That is, K.E = 1/2mv^2 = F × s

Where workdone = Force × distance

Make F the subject of formula

Mv^2/2s = F

But V = distance s/time t

Substitute for V

Ms^2/2t^2s = F

Ms/2t^2 = F

From the equation above, we can deduce that F is inversely proportional to the square of time.

Therefore, the reduced impact time will increase the impact force

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A hole is drilled in a metal plate. When the metal is raised to a higher temperature, what happens to the diameter of the hole?
zysi [14]

Answer:

The diameter of the hole increases

Explanation:

Metals expand and contract with temperature. Whenever metal is heated, it usually expands in relation to its thermal expansivity. This expansion leads to a slight increase in surface area.

Once the surface area of the metal changes, this means that the dimensions of the whole metal surface changed. As a result, the diameter of the hole drilled in the metal plate will change also. In our case, the diameter of the hole will increase.

4 0
3 years ago
Find a numerical value for rhoearth, the average density of the earth in kilograms per cubic meter. Use 6378km for the radius of
mylen [45]

Answer:

density = 5520 kg/m^3

Explanation:

given that

radius of earth = 6378 km

G = 6.67 x 10⁻¹¹ m³/kg.s²

g = 9.80 m/s²

we know,

g = \dfrac{GM}{r^2}

mass of earth

M = \dfrac{gr^2}{G}

M = \dfrac{9.8 \times (6378 \times 10^3)^2}{6.67 \times 10^{-11}}

M = 5.972 x 10²⁴ kg

density =\dfrac{mass}{volume}

V = volume of the earth = 4/3πr³

V = 4/3 x 3.14 x (6378  x 10³)³

V = 1.08 x 10²¹ m³

density = \dfrac{5.972\times 10^{24}}{1.08\times 10^{21}}

density = 5.52 x 10³  kg/m^3

density = 5520 kg/m^3

8 0
3 years ago
Soil conservation involves protecting _______ and preventing _______.
horrorfan [7]
<span>Soil conservation involves protecting soil quality and preventing erosion.
Answer: A</span>
8 0
3 years ago
Read 2 more answers
If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the 1200.-kg pick-up truck behind him continues tr
Alborosie

Answer: 20.2 m/s

Explanation:

From the question above, we have the following data;

M1 = 800kg

M2 = 1200kg

V1 = 13m/s

V2 = 25m/s

U (common velocity) =?

M1V1 + M2V2 = (M1 + M2). U

(800*13) + (1200*25) = (800+1200) * U

10400 + 30000 = 2000u

40400 = 2000u

U = 40400 / 2000

U = 20.2 m/s

5 0
3 years ago
Read 2 more answers
How does a fuse work?
Vilka [71]

Answer:

A. a material burns out when current is excessive

5 0
3 years ago
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