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Allushta [10]
3 years ago
13

HURRY PLEASE

Physics
1 answer:
Aneli [31]3 years ago
8 0

Answer:

I think that the answer is the first or third one

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What is potential energy??​
Murrr4er [49]

Answer:

the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

hope this helps

have a good day :)

Explanation:

3 0
3 years ago
Read 2 more answers
A student holds a bike wheel and starts it spinning with an initial angular speed of 9.0 rotations per second. The wheel is subj
zloy xaker [14]

Answer:

T = 0.00889 N*m

Explanation:

Given the initial speed

Vo = 9.0rev/s.

V = 65 rev/10s

V = 6.5 rev/s.

V = Vo + a*t

Solve to acceleration knowing the initial velocity and the velocity at 10 s

6.5 rev/s - 9 rev/s = a*10s

a = -0.25 rev/s^2.

Now the solve the time at stop time so V=0

V = Vo + a*t

0 = 9.0 - 0.25 rev/s *t,

t = 36 s The Stopping time.

36s -  10s = 26s

The torque can be find using the acceleration using the equation

T = I*a

I = 1/2*m*r^2

I = 1/2*0.725kg*(0.315m)^2= 0.0359kg*m^2

T = 0.0359kg*m^2*-0.25rev/s^2

T = 0.00889 N*m

7 0
3 years ago
How does the toaster serve as an example of Convection energy transfer?
blsea [12.9K]
Check bing for the answer
3 0
3 years ago
A car traveling at 40 ft/sec decelerates at a constant 5 feet per second per second. how many feet does the car travel before co
Tema [17]
<span>This problem is solved by the equation of motion: x = x0 + v0*t + 1/2*a*t^2, Here x0 = 0, v0 = 40ft/sec and a = -5 ft/s^2, we need to solve for t: v = v0 + a*t, solve how long does it take to stop: 0 = v0 + a*t --> a*t = -v0 --> t = -v0/a -- > 40/5 = 8 seconds to stop. In this time, the car travels x = 0 + 40*8 + 0.5*-5*8^2 ft ~ 160 ft. Answer: The car travels 160 ft.</span>
3 0
3 years ago
A uniform 4.4 t magnetic field points north. if an electron moves vertically downward (toward the ground) with a speed of 2.5 ×
Reil [10]

Answer:

1.8\cdot 10^{-11} N

Explanation:

The force acting on the electron due to the magnetic field is

F=qvB sin \theta

where

q=1.6\cdot 10^{-19} C is the charge of the electron

v=2.5\cdot 10^7 m/s is its speed

B=4.4 T is the intensity of the magnetic field

\theta=90^{\circ} is the angle between the direction of the field and the velocity of the electron

Substituting all the numbers into the equation, we find

F=(1.6\cdot 10^{-19}C)(2.5\cdot 10^7 m/s)(4.4 T) sin 90^{\circ}=1.8\cdot 10^{-11} N

8 0
4 years ago
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