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Allushta [10]
2 years ago
13

HURRY PLEASE

Physics
1 answer:
Aneli [31]2 years ago
8 0

Answer:

I think that the answer is the first or third one

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Question 16 of 20 You plan to use a slingshot to launch a ball that has a mass of 0.023 kg. You want the ball to accelerate stra
liubo4ka [24]

Answer:

this is a simple application of Newton's 2nd Law: F = ma.

F = 0.023(25)

So,

F =0.575 N.

Therefore

The answer is A.

If rounded up/off.

Explanation:

HOPE IT HELPS.

PLEASE MARK AS BRAINLIEST.

4 0
2 years ago
Which describes Einstein’s second postulate about the special theory of relativity? The speed of light in a vacuum is constant,
crimeas [40]

Answer:A

Explanation:

5 0
2 years ago
Read 2 more answers
A block of weight mg sits on an inclined plane as shown in (Figure 1) . A force of magnitude F1 is applied to pull the block up
svlad2 [7]

Answer:

W = (F1 - mg sin θ) L,   W = -μ  mg cos θ L

Explanation:

Let's use Newton's second law to find the friction force. In these problems the x axis is taken parallel to the plane and the y axis perpendicular to the plane

Y Axis  

       N - W_{y} =

       N = W_{y}

X axis

       F1 - fr - Wₓ = 0

       fr = F1 - Wₓ

Let's use trigonometry to find the components of the weight

     sin θ = Wₓ / W

     cos θ = W_{y} / W

      Wₓ = W sin θ

      W_{y} = W cos θ

We substitute

      fr = F1 - W sin θ

Work is defined by

        W = F .dx

        W = F dx cos θ

The friction force is parallel to the plane in the negative direction and the displacement is positive along the plane, so the Angle is 180º and the cos θ= -1

         

        W = -fr x

        W = (F1 - mg sin θ) L

Another way to calculate is

         fr = μ N

         fr = μ W cos θ

the work is

         W = -μ  mg cos θ L

4 0
3 years ago
In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg. After the two
IrinaVladis [17]

This question involves the concepts of the law of conservation of momentum.

The magnitude of the final momentum of the eight ball is "0.22 N.s".

According to the law of conservation of momentum:

P_{i1}+P_{i2}=P_{f1}+P_{f2}

where,

P_{i1} = initial momentum of the cue ball = 0.23 N.s

P_{i2} = initial momentum of the eight ball = 0 N.s (since ball is initially at rest)

P_{f1} = final momentum of the cue ball = 0.01 N.s

P_{f2} = final momentum of the eight ball = ?

Therefore,

0.23\ N.s + 0\N.s = 0.01\ N.s+P_{f2}\\\\P_{f2} = 0.22\ N.s

Learn more about the law of conservation of momentum here:

brainly.com/question/1113396?referrer=searchResults

3 0
2 years ago
A standard 1 kilogram weight is a cylinder 41.5 mm in height and 44.0 mm in diameter. what is the density of the material?
Korvikt [17]

Answer;

=15855.40 kg/m^3

Explanation;

Volume (V) of the cylinder = pi x r^2 x h  

V = 3.14 x (44/2 x 10^-3)^2 x 41.5 x 10^-3  

V = 6.307 x 10^-5 m^3  

By density = m/V  

mass = 1 kg

density = 1/(6.307 x 10^-5) = 15855.40 kg/m^3

6 0
3 years ago
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