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shusha [124]
2 years ago
5

30 points ᖗ☯ ͟ل͜☯ᖘ

Physics
1 answer:
Butoxors [25]2 years ago
6 0
1. Magnetic properties of a substance depends on the structure of its valence electrons. It has something to do with orbitals so I suggest you study about molecular geometry of a compound/substance firstIt's the way a substance's atoms fit together, being pulled and pushed from all sides equally. exists in metallic bonds <span>if a substance is said to be magnetic, it is simply attracted by a magnet. if it is paramagnetic, it is repelled by a magnet.

2.</span>The magnetic field will be perpendicular to the electric field and vice versa<span> An electric field is the area which surrounds an electric charge within which it is capable of exerting a perceptible force on another electric charge. A magnetic field is the area of force surrounding a magnetic pole, or a current flowing through a conductor, in which there is a magnetic flux. A magnetic field can be produced when an electric current is passed through an electric circuit wound in a helix or solenoid. The relationship that exists between an electric field and a magnetic field is one of electromagnetic interaction as a consequence of associating elementary particles. The electrostatic force between charged particles is an example of this relationship.</span>
You might be interested in
Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those a
Nat2105 [25]

Answer:

Explanation:

Given

diameter d=20 \mu m

density \rho =1300 kg/m^3

frequency \nu =150 Hz

Length of silk strand L=14 cm

Velocity in the string is as follows

\nu =\sqrt{\frac{T}{\mu }}

The expression for Fundamental Frequency

f=\frac{\nu }{2l}

f=\frac{1}{2l}\times \sqrt{\frac{T}{\mu }}

f=\frac{1}{2l}\times \sqrt{\frac{T}{\frac{m}{l}}}

f=\frac{1}{2l}\times \sqrt{\frac{Tl}{\rho V}}

Squaring

f^2=\frac{1}{4l^2}\times \frac{Tl}{\rho V}

T=4\rho \cdot A\cdot l^2\cdot f^2

T=4\times 1300\times \frac{\pi }{4}(20\times 10^{-6})^2\times (0.14)^2\times 150^2

T=7.2\times 10^{-4} N

8 0
3 years ago
An object that has lost its electrons become?​
Andrej [43]
Answer: A positively charged ion/ cation

Explanation: When an atom loses all of its electrons, it becomes a positively charged ion. Also referred to as the cation, the object will have a shortage of electrons, leading to a positive charge. Keep in mind that an atom will become positive if it loses electrons, and will become negative if it gains electrons.


Hope this helps! Comment below for more questions.
7 0
2 years ago
chris and molly wins $2400 in a competition they share the money in the ratio2:3 how much money do they each receive ?​
nlexa [21]

Answer:

chris gets 960 and molly gets 1440

Explanation:

add the ratio up and divide

2+3=5

2400/5=480

480x2=960

480x3=1440

960+1440= 2400

5 0
3 years ago
Un cuerpo se mueve, partiendo del reposo, con una aceleración constante de 8 m/s². Calcular la velocidad que tiene al cabo de 5s
nataly862011 [7]

Answer:

v = 40 m / s

Explanation:

Let's use the expressions for accelerated motion

         v = v₀ + a t

where vo is the initial velocity, at the acceleration and t is the time.

as the body starts from rest its initial velocity is zero

         v = 0 + at

let's calculate

         v = 8  5

         v = 40 m / s

8 0
2 years ago
A 10-cm-long spring is attached to theceiling. When a 2.0 kg mass is hung from it,the spring stretches to a length of 15 cm.a.Wh
alekssr [168]

(a) 392 N/m

Hook's law states that:

F=k\Delta x (1)

where

F is the force exerted on the spring

k is the spring constant

\Delta x is the stretching/compression of the spring

In this problem:

- The force exerted on the spring is equal to the weight of the block attached to the spring:

F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N

- The stretching of the spring is

\Delta x=15 cm-10 cm=5 cm=0.05 m

Solving eq.(1) for k, we find the spring constant:

k=\frac{F}{\Delta x}=\frac{19.6 N}{0.05 m}=392 N/m

(b) 17.5 cm

If a block of m = 3.0 kg is attached to the spring, the new force applied is

F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N

And so, the stretch of the spring is

\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm

And since the initial lenght of the spring is

x_0 = 10 cm

The final length will be

x_f = x_0 +\Delta x=10 cm+7.5 cm=17.5 cm

8 0
3 years ago
Read 2 more answers
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