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2 years ago

Explain how a cold compress used by

Chemistry

1 answer:

Fynjy0 [20]2 years ago

7 0

Answer: A cold compress used by athletes is an endothermic reaction.

Explanation:

A pack of cold compress used by athletes contains water that holds another bag or tube inside it which is filled with ammonium nitrate fertilizer.

So, on hitting the cold compress the tube breaks down due to which fertilizer gets mixed with water. This mixture absorbs the heat when placed on the area of body having pain, strain or bump.

As a result, we tend to feel cold at the affected area of our body.

Thus, we can conclude that a cold compress used by athletes is an endothermic reaction.

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Complete and balance the following acid-base reaction equation ______HNO3 + ______ Mg(OH)2 ------>

jekas [21]

Answer

_2 HNO₃ + 1 Mg(OH)₂ → 1 Mg(NO₃)₂ + 2 H₂O

Explanation

Given:

______HNO3 + Mg(OH)2 ------>

Solution:

Note that the reaction between an acid and a base will give salt and water only.

Hence the complete reaction of the given equation is:

___HNO₃ + Mg(OH)₂ → Mg(NO₃)₂ + H₂O

To get the balanced equation for the acid-base reaction, 2 moles of HNO₃ will react with 1 mole of Mg(OH)₂ to produced 1 mole of Mg(NO₃)₂ and 2 moles of H₂O.

Therefore, the complete and balanced equation for the given acid-base reaction is:

_2 HNO₃ + 1 Mg(OH)₂ → 1 Mg(NO₃)₂ + 2 H₂O

5 0

11 months ago

What moves the pieces of salt on top of the speaker when the music is playing

Ksivusya [100]

Answer:

the friction?? or the movement

Explanation:

sense the salt is so light its easy to move

5 0

3 years ago

A volume of 80.0 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. I

murzikaleks [220]

Answer:

The mass of the steel bar is 26.833 grams

Explanation:

<u>Step 1: </u>data given

ΣQ gained = ΣQ lost

Q=m*C*ΔT

with m = mass in grams

with C= specific heat capacity ( in J/(g°C))

with ΔT = change in temperature = T2-T1

Qsteel = Qwater

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

Mass of steel = TO BE DETERMINED

mass of water =⇒ since 1mL = 1g : 80 mL = 80g

Csteel =0.452 J/(g °C

Cwater = 4.18 J/(g °C

initial temperature steel T1 : 2 °C

final temperature steel T2 = 21.3 °C

initial temperature water T1 =22 °C

final temperature water T2 = 21.3 °C

<u>Step 2:</u> Calculate mass of steel

msteel * Csteel * (T2steel - T1steel) = mwater * Cwater * (T2water - T1water)

msteel * 0.452 *(21.3-2) = 80 * 4.18 * (21.3-22)

msteel = (80 * 4.18 * (-0.7)) / (0.452 * 19.3)

msteel = -234.08 / 8.7236

msteel = -26.833 g

Since mass can't be negative we should take the absolute value of it = 26.833g

The mass of the steel bar is 26.833 grams

6 0

2 years ago

Using the Polymers: A Property Database provide the following

Novosadov [1.4K]

Polyethene is a polymer composed of repeating units of the monomer ethene.

The properties of polyethene are as follows:

density- ranges 0.857 g/cm3 to 0.975 g/cm3.
specific heat capacity is 1.9 kJ/kg.
melting temperature is approximately 110 °C.

<h3>What are polymers?</h3>

Polymers are large macromolecules consisting of long repeating chains of smaller molecules known as monomers.

An example of a polymer is polyethene composed of repeating units of the monomer ethene.

The density of polyethylene ranges 0.857 g/cm3 to 0.975 g/cm3.

The specific heat capacity of polyethene is 1.9 kJ/kg.

The melting temperature of polyethene is approximately 110 °C.

Learn more about polyethene at: brainly.com/question/165779

4 0

1 year ago

In Universe L, recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quan

lidiya [134]

Answer:

Second element(Titanium); [Ar] 3d2 4s2

Third element(Vanadium):Ar 3d3 4s2

Explanation:

Given that there are only three d orbitals in universe L instead of five, the electronic configuration of the second and third elements in the first transition series will now look thus;

Second element(Titanium); [Ar] 3d2 4s2

Third transition element(Vanadium):Ar 3d3 4s2

Hence, the electronic configuration of Titanium and Vanadium in universe L is just the same as what it is on earth.

6 0

2 years ago