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hjlf
2 years ago
14

At 9:00 a.m. Monday morning, Thomas fills a beaker with water and places it in the corner of the classroom. At 1:00 p.m. on Tues

day, Thomas examines the beaker and notices that the water level is 42 milliliters. At 11:00 a.m. on Wednesday, the water level has dropped to 31 milliliters. If the evaporation of the water follows a linear function, at what time will the beaker be empty?.
Chemistry
2 answers:
Nitella [24]2 years ago
6 0

Answer is: will the beaker be empty Saturday 1:00 am.

l₁ = 42 mL; water level at Tuesday.

l₂ = 31 mL; water level at Wednesday.

Δl = l₁ - l₂.

Δl = 42 mL - 31 mL.

Δl = 11 mL; difference between water levels.

Δt = 22 h; difference in time.

rate of evaporation = Δl ÷ Δt.

rate of evaporation = 11 mL ÷ 22 h.

rate of evaporation = 0.5 mL/h.

t = 31 mL ÷ 0.5 mL/h.

t = 62 h; time needed for empty the beaker.

zmey [24]2 years ago
3 0
Given the data level decreased to 31 milliliters from 42 milliliters for 22 hrs (the difference of height is 11 milliliters) we take the rate of height depreciation of 0.5 mL/ hour. In this case, to drain out all 31 milliliters, a total of 62 hrs must be alloted. 62 hours is equal to 2 days and 14 hrs. Hence the day which the beaker becomes empty is Saturday at 1 am. 
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Easy stoichiometry conversion :)

So, for stoichiometry, we always start with our "given". In this case, it would be the 10.0 grams of NaHCO3. This unit always goes over 1.

So, our first step would look like this:

10.0
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Next, we need to cancel out grams to get to moles. To do this, we will do grams of citric acid on the BOTTOM of the next step, so it cancels out. This unit in grams will be the mass of NaHCO3, which is 84.007. Then, we will do our unit of moles on top. Since this is unknown, it will be 1.

So, our 2nd step would look like this:

1 mole CO2
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84.007g NaHCO3

When we put it together: our complete stoichiometry problem would look like this:

10.0g NaHCO3     1mol CO2
---------------------- x -------------------------
            1                  84.007g NaHCO3

Now to find our answer, all we need to do is:
Multiply the two top numbers together (which is 10.0)
Multiply the two bottom numbers together (Which is 84.007)

And then....

Divide the top answer by the bottom answer.

10.0/84.007 is 0.119

So, from 10.0 grams of citric acid, we have 0.119 moles of CO2.

Hope I could help!
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Answer:

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Explanation:

The combined gas equation is,

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