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Anton [14]
3 years ago
11

A scientist uses a variable frequency microphone/speaker system (sonar) to measure the depth of water. In freshwater (were sound

travels at 1490 m/s) and 120 Hz sound is sent from a stationary ship to the bottom of a deep lake and the time interval between the generation and detection of the echo takes 1.14 seconds.
What is the distance from the ship to the bottom of the lake?
Physics
1 answer:
jok3333 [9.3K]3 years ago
5 0
Bsnsjsjsussnshsnsnszjksmsjshsneh
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BUT WHY

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A cylindrical container with a cross sectional area of 65.2 cm^2 holds a fluid of density 806 kg/m^3. At the bottom of the conta
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The right answer is (b)
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What is element ratio?
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A ratio is a way to compare quantities of things.

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A charged balloon will stick to a neutral wall. which process is involved?
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<span>The charged balloon will stick to a neutral wall because of the Static Electricity:
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 The matter is formed by atoms and these atoms are composed of electrons, protons and neutrons (the electrons have a negative charge, the protons have a positive charge and the neutrons have no charge).

 As the balloon is charged (It gained electrons), and the charge of the same sign repel each other, when it approaches the wall, the electrons of this wall will move away, and the positive charges (protons) will remain in the nearest area to the balloon. As the charges of different signs are attracted, the balloon will be stuck to the wall.
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4 years ago
The energy levels of one‑electron ions are given by the equation En=(−2.18×10−18 J)(Z^2/n^2) where Z is atomic number and n is t
Alexxandr [17]

Answer:

\lambda=4.86*10^{-7}m

Explanation:

Using the given equation, we calculate the energy associated with the excited state n_i=8 and n_f=4

E_n=\frac{-2.18*10^-18J(Z^2)}{n^2}

Helium has an atomic number (Z) equal to 2, for n=8:

E_8=\frac{-2.18*10^{-18}J(2^2)}{8^2}\\E_8=-1.36*10{-19}J

For n=4:

E_4=\frac{-2.18*10^{-18}J(2^2)}{4^2}\\E_4=-5.45*10{-19}J

When an electron jumps from an energy level with greater energy E_i to one with lower energy E_f the wavelength of the emitted photon is given by:

\lambda=\frac{hc}{E_i-E_f}

h is the Planck constant and c the speed of light in vaccum. So, we have:

\lambda=\frac{hc}{E_8-E_4}\\\lambda=\frac{6.63*10^{-34}J \cdot s(3*10^8\frac{m}{s})}{-1.36*10{-19}J-(-5.45*10{-19}J)}\\\lambda=4.86*10^{-7}m

5 0
3 years ago
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