You pick up the hula hoop and stand inside of it then pick it up will you’re inside it and hold to your waist and spin it then turn your hips
To solve this problem we will use the concepts related to hydrostatic pressure. Which determines the pressure of a body at a given depth of a liquid.
Mathematically this can be described as
Here
= Density
g = Gravity
h = Height (Depth)
If we replace the values given in the equation we will have to
Therefore the pressure at the bottom will be 9.8kPa
Answer: C
Explanation: On the top edge.
Answer:
414.9 m
Explanation:
First, become familiar with the horizontal, and vertical vector components.
Vertical vector: Vy = V × sin (θ).
Horizontal vector: Vx = V × cos(θ).
Distance traveled = Velocity vector × time in the air.
Time in the air given Vy = 2 × Vy / g (in respect to the metric of the vector).
Range of the projectile = Vx² / g
Time in the air given Vx = (Vx + √(Vx)² + 2gh) / g.
Given a 28° angle with an initial velocity of 70m/s, we have enough information to calculate!
Vx = 70 m/s × cos(28°) ≈ 61.806 m/s
Vy = 70 m/s × sin(28°) ≈ 32.863 m/s
t = 2 × Vy / g
t = 2 × ≈32.863 / 9.8
t = ≈65.726 / 9.8
t ≈ 6.7 s
Distance traveled (horizontal) = Vx × t = 61.806 × 6.7 ≈ 414.9 m
If a balloon is high up it will pop because pressure here think of it like this when you swim and go under water lets say 12ft you will notice that your head will hurt and it will take your oxygen away faster just like a balloon it has air in it so when it goes to high it will pop because its made of weak material so it will pop. and a low balloon because it will hit things and like i said balloons pop easy it could also get soft rubber because it is not moving and if like the sun was on it than it would pop as well i really hope this helped you
