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Zinaida [17]
4 years ago
12

Soccer ball is heading east positive direction with momentum of 2kgm/s. It is kicked backwards and a fraction of a second later

is moving west negative direction withmomentum of -2.3. What impulse did the kicker put on the ball on kgm/s?
Physics
1 answer:
attashe74 [19]4 years ago
8 0

Answer:

-4.3 kgm/s

Explanation:

Impulse which the soccer ball experiences is equal to the change in momentum of a body.

It is given mathematically as:

Impulse = m*Δv = mv - mu

Initial momentum of soccer ball = 2 kgm/s

Final momentum of the soccer ball = -2.3 kgm/s

Therefore, Impulse will be:

Impulse = -2.3 - 2

Impulse = -4.3 kgm/s

The impulse put on the soccer ball by the kicker is -4.3 kgm/s.

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A 12 kg box is pulled across the floor with a 48 N horizontal force. If the force of friction is 12 N, what is the acceleration
Oksi-84 [34.3K]

Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

7 0
3 years ago
The triceps muscle in the back of the upper arm extends the forearm. This muscle in a professional boxer exerts a force of 2551
RUDIKE [14]

Answer:

0.7 kg m²

Explanation:

F = force exerted applied by muscle in a professional boxer = 2551 N

r = length of lever arm = 3.15 cm = 0.0315 m

α = angular acceleration of the forearm = 115 rad/s²

I = moment of inertia of the boxer's forearm

τ = Torque applied by muscle in a professional boxer

Torque is given as

τ = I α = r F

Inserting the values

I (115) = (0.0315) (2551)

I = 0.7 kg m²

7 0
3 years ago
Square root of 40 as a fraction
AysviL [449]

Answer:

158/25

Explanation:

I really hope I helped you!!

Have a good day! :)

8 0
3 years ago
A load of 54 N attached to a spring that ishanging vertically stretches the spring 0.15 m.What is the spring constant?Answer in
beks73 [17]

Answer:

300 N/m

Explanation:

given,

Load attached to the spring, W = 54 N

length of stretch of the spring, x = 0.15 m

spring constant= ?

Force applied on the spring is calculated by the equation

F = k x

where k is the spring constant

x is the displacement of the spring due to applied load

now,

54 = k × 0.15

k = \dfrac{54}{0.15}

k =300\ N/m

hence, the spring constant is equal to 300 N/m

8 0
4 years ago
Read 2 more answers
abody starts from rest and accelerate uniformly at 8m/s/s.calculate the distance travelled by the body in 10s? ​
vagabundo [1.1K]

Explanation:

using the formula: S=ut+½gt², where u=0, S=?, g=8m/s², t=10seconds.

S=ut+½gt² ("ut" term will cancel because u=0).

=> S= ½gt²

=>S = ½×8×10²

=>S = 4×100

=>S = 400m .

Therefore, the distance traveled by the body in 10s is 400m.

hope this helps you.

6 0
2 years ago
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