Someone do this please
2 answers:
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Answer:
Mass of rock = 4533.4 kg
Explanation:
Percent composition is percentage by the mass of element present in the compound.
Given that the is 82 % by mass.
It means that 82 kg of is present in 100 kg of rock
To find the mass of rock which contains 2600 kg of iron
2600 kg = 2600*1000 g
2 moles of iron are present in 1 mole of
Molar mass of iron = 55.845 g/mol
Mass of 2 moles = 55.845 * 2 = 111.69 g/mol
Molar mass of = 159.69 g/mol
It means,
111.69 g of iron are present in 159.69 g of
1 g of iron is present in 159.69/111.69 g of
2600*1000 g is present in (159.69/111.69)*2600*1000 g of
Mass of = 3717378.47 g =3717.38 kg
Thus,
82 kg of is present in 100 kg of rock
1 kg of is present in 100/82 kg of rock
3717.38 kg of is present in (100/82)*3717.38 kg of rock
Mass of rock = 4533.4 kg