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Olin [163]
2 years ago
14

PLEASE HELP 50 POINTS!!!!!

Chemistry
1 answer:
OLEGan [10]2 years ago
8 0

Answer: This is what an effective conclusion should include.

Restate: Restate the lab experiment. Describe the assignment.

Explain: Explain the purpose of the lab. What were you trying to figure out or discover? ...

Results: Explain your results. ...

Uncertainties: Account for uncertainties and errors. ...

New: Discuss new questions or discoveries that emerged from the experiment.

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What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?
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The dilution formula can be used to find the volume needed

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

c1 - 0.33 M

c2 - 0.025 M

v2 - 25 mL

Substituting these values in the equation

0.33 M x v1 = 0.025 M x 25 mL

v1 = 1.89 mL

Therefore 1.89 mL of the 0.33 M solution needs to be diluted up to 25 mL to make a 0.025 M solution

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It is the smallest unit it is what makes up everything

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Draw a bond-line structure for CH3CH2O(CH2)2CH(CH3)2.<br><br> Include Lone Pairs in your answer.
mash [69]

Answer:

See explanation and image attached

Explanation:

A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.

The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.

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