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3 years ago

Simplify these expressions a) 2a + 5a b) 12x - 3x c) 3p + 2p-p

Mathematics

2 answers:

pentagon [3]3 years ago

7 0

a) The two parts of this expression, +2a and +5a are called terms and

the numbers in front of the variables, +2 and +5 are called coefficients.

Because the variables, a and a, are identical,

the two terms in this problem are called like terms.

Like terms can be added together by simply adding their coefficients.

So in this problem, since 2 + 5 is 7, 2a + 5a is simply 11a.

b) Since both terms contain an x, we can subtract them.

Also, change the minus to plus a negative.

So we have 12x + -3x which simplifies to 9x.

c) If there is no coefficient in front of the variable, you can give it

a coefficient of 1, so -p can be thought of as -1p.

So we have 3p + 2p -1p which is 4p.

Gnom [1K]3 years ago

3 0

A) 7a
B)9x
C)4p

In the first question you needed to add the 2 expressions, because they contain the same letter you can just add them

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Read 2 more answers

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trapecia [35]

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First parameterize the pieces of the contour:

$C_1:\mathbf r_1(t_1)=(2\sin t_1,2\cos t_1,0)$
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where $0\le t_1\le\dfrac\pi2$ and $0\le t_2\le1$ . You have

$\mathrm d\mathbf r_1=(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
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and so the work is given by the integral

$\displaystyle\int_C\mathbf F(x,y,z)\cdot\mathrm d\mathbf r$
$=\displaystyle\int_0^{\pi/2}\mathbf F(2\sin t_1,2\cos t_1,0)\cdot(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1$
${}\displaystyle\,\,\,\,\,\,\,\,+\int_0^1\mathbf F(2+t_2,3t_2,3t_2)\cdot(1,3,3)\,\mathrm dt_2$