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brilliants [131]
3 years ago
13

Now that you’ve verified there’s current through the electromagnet, uncheck the Show Electrons box. This action turns off the el

ectrons. (The current is still there; we just don’t see it.) Check the Show Compass box. Move the compass to the bottom right side of the coil. Does the electromagnet affect the compass needle?
Physics
2 answers:
ale4655 [162]3 years ago
7 0

yeah, it affects the needle

bearhunter [10]3 years ago
3 0

Yes, the electromagnet still affects the compass needle.

(plato answer)

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Consider 3.5 kg of austenite containing 0.95 wt% c and cooled to below 727°c (1341°f). (a) what is the proeutectoid phase? (b) h
vladimir2022 [97]
A. The proeutectoid phase is Fe₃c because 0.95 wt/c  is greater than the eutectoid composition which is 0.76 wt/c

b.  We determine how much total territe and cementite form, we apply the lever rule expressions yields.
Wx = (fe₃c-co/cfe₃ c-cx = 6.70- 0.95/6.70- 0.022 = 0.86
The total cementite
Wfe₃C = 10-Cx/ Cfe₃c -Cx = 0.95 - 0.022/6.70 - 0.022 = 0.14
The total cementite which is formed is 
(0.14) × (3.5kg) = 0.49kg

c.  We calculate the pearule and the procutectoid phase which cementite form the equation
Ci = 0.95 wt/c
Wp = 6.70 -ci/6.70 - 0.76 = 6.70 -0.95/6.70 - 0.76 = 0.97
0.97 corresponds to mass.
W fe₃ C¹ = Ci - 0.76/5.94 = 0.03
∴ It is equivalent to 
(0.03) × (3.5) = 0.11kg of total of 3.5kg mass.
4 0
3 years ago
A loop of area 0.250 m^2 is in a uniform 0.020 0-T magnetic field. If the flux through the loop is 3.83 × 10-3T· m2, what angle
Nostrana [21]

Answer:

40.0⁰

Explanation:

The formula for calculating the magnetic flux is expressed as:

\phi = BAcos\theta where:

\phi is the magnetic flux

B is the magnetic field

A is the cross sectional area

\theta is the angle that the normal to the plane of the loop make with the direction of the magnetic field.

Given

A = 0.250m²

B = 0.020T

\phi = 3.83 × 10⁻³T· m²

3.83 × 10⁻³ = 0.020*0.250cosθ

3.83 × 10⁻³ = 0.005cosθ

cosθ = 0.00383/0.005

cosθ = 0.766

θ = cos⁻¹0.766

θ = 40.0⁰

<em>Hence the angle normal to the plane of the loop make with the direction of the magnetic field is 40.0⁰</em>

6 0
3 years ago
A local company is expanding its business and is working to build an eco-friendly building with a modern artistic design. Larry
KATRIN_1 [288]

Answer: I think the answer is C

Larry is an architectural drafter Francis is an architect Meka is a construction manager and Lacey's interior designer.

3 0
3 years ago
Read 2 more answers
A cart on a horizontal, linear track has a fan attached to it. The cart is positioned at one end of the track, and the fan is tu
kompoz [17]

Answer:

a

  F = 0.0566 \  N  

b

   t =  6.147 \  s

Explanation:

From the question we are told that

     The distance travel in  4.22 s is  s =  1.44 \ m

     The mass of the cart plus the fan is  m  =  350 \  g =  0.35 \  kg

Generally from kinematic equation we have that

        s =  ut + \frac{1}{2}  * a * t^2

Here  u is the initial  velocity with value  u =  0 \ m/s

So  

         1.44=  0 * t + \frac{1}{2}  *  a * 4.22^2      

=>      a =  0.1617 \  m/s^2

Generally the net force is  

         F = m * a

=>      F = 0.35  *  0.1617  

=>      F = 0.0566 \  N  

Gnerally the new mass of the cart plus the fan is  M  =  656 \  g  = 0.656 \  kg

    The distance considered is s_1 = 1.63 \  m

     Generally the new acceleration of the cart is mathematically represented as

        F =  M  *  a_1

=>      a_1 =  \frac{F}{M}

=>      a_1 =  \frac{0.0566}{0.656}

=>      a_1 = 0.08628 \  m/s^2

Gnerally from kinematic equation we have

          s =  ut + \frac{1}{2} *  a_1 *  t ^2

Here u  is the initial velocity and the value is zero because it started from rest  

=>       1.63 =  0 * t + \frac{1}{2} *  0.08628*  t ^2

=>        t =  6.147 \  s

6 0
3 years ago
What data will you collect in order to calculate the balloon car’s velocity?
Anvisha [2.4K]

Answer:

To calculate speed, all you have to do is divide distance by time.

Explanation:

Velocity is just speed in a particular direction. For example, if in 3 hours you ran 6 kilometers west, your velocity was 6 km/3 hours = 2 km/hour west.

7 0
3 years ago
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