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Lubov Fominskaja [6]
3 years ago
5

Find the number of faces, edges, and vertices of this shape.​

Mathematics
2 answers:
aliya0001 [1]3 years ago
4 0
Faces:7

Vertices:12

Edges:7
sattari [20]3 years ago
3 0
Faces: 7

Edges: 12

Vertices: 7
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Answer:$79.25

Step-by-step explanation:

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Q=P(R+R) (SOLVE FOR P)
forsale [732]
Isolate the variable by dividing each side by factors that don't contain the variable. p=q/2r
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What is the solution of log2x+3125 = 3? (1 point)
enot [183]

Answer:

x =  - 1062.5

Step-by-step explanation:

Assuming the equation is:

log(2x + 3125)  = 3

Then taking antilogarithms gives:

2x + 3125 =  {10}^{3}

We simplify on the left to get:

2x + 3125 = 10 \times 10 \times 10

This gives us:

2x + 3125 =1000

We subtract 3125 from both sides to get:

2x = 1000 - 3125

2x = -  2125

x =  - 1062.5

6 0
3 years ago
What is the diameter of the circle that has a radius of 6
pav-90 [236]

Answer:

12 units

Step-by-step explanation:

The radius is half of the diameter, so we need to double 6 to get 12.

7 0
3 years ago
Read 2 more answers
The volume of a sphere whose diameter is 18 centimeters is _ cubic centimeters. If it’s diameter we’re reduced by half, it’s vol
kaheart [24]
<h2>Answer:</h2>

<u>First Part</u>

Given that

Volume = \frac{4}{3} \pi r^{3}

We have that

Volume = \frac{4}{3} \pi r^{3} =  \frac{4}{3} \pi (\frac{Diameter}{2})^{3} =  \frac{4}{3} \pi 9^{3} = 972\pi cm^{3} \approx 3053.63 cm^{3}

<u>Second Part</u>

Given that

Volume = \frac{4}{3} \pi r^{3}

If the Diameter were reduced by half we have that

Volume = \frac{4}{3} \pi r^{3} =  \frac{4}{3} \pi (\frac{r}{2}) ^{3} = \frac{\frac{4}{3} \pi r^{3}}{8}

This shows that the volume would be \frac{1}{8} of its original volume

<h2>Step-by-step explanation:</h2>

<u>First Part</u>

Gather Information

Diameter = 18cm

Volume = \frac{4}{3} \pi r^{3}

Calculate Radius from Diameter

Radius = \frac{Diameter}{2} = \frac{18}{2} = 9

Use the Radius on the Volume formula

Volume = \frac{4}{3} \pi r^{3} =  \frac{4}{3} \pi 9^{3}

Before starting any calculation, we try to simplify everything we can by expanding the exponent and then factoring one of the 9s

Volume = \frac{4}{3} \pi 9^{3} = \frac{4}{3} \pi 9 * 9 * 9 = \frac{4}{3} \pi 9 * 9 * 3 * 3

We can see now that one of the 3s can be already divided by the 3 in the denominator

Volume = \frac{4}{3} \pi 9 * 9 * 3 * 3 = 4 \pi 9 * 9 * 3

Finally, since we can't simplify anymore we just calculate it's volume

Volume = 4 \pi 9 * 9 * 3 = 12 \pi * 9 * 9 = 12 * 81 \pi = 972 \pi cm^{3}

Volume \approx 3053.63 cm^{3}

<u>Second Part</u>

Understanding how the Diameter reduced by half would change the Radius

Radius =\frac{Diameter}{2}\\\\If \\\\Diameter = \frac{Diameter}{2}\\\\Then\\\\Radius = \frac{\frac{Diameter}{2} }{2} = \frac{\frac{Diameter}{2}}{\frac{2}{1}} = \frac{Diameter}{2} * \frac{1}{2} = \frac{Diameter}{4}

Understanding how the Radius now changes the Volume

Volume = \frac{4}{3}\pi r^{3}

With the original Diameter, we have that

Volume = \frac{4}{3}\pi (\frac{Diameter}{2}) ^{3} = \frac{4}{3}\pi \frac{Diameter^{3}}{2^{3}}\\\\ = \frac{4}{3}\pi \frac{Diameter^{3}}{2 * 2 * 2} = \frac{4}{3}\pi \frac{Diameter^{3}}{8}\\\\

If the Diameter were reduced by half, we have that

Volume = \frac{4}{3}\pi (\frac{Diameter}{4}) ^{3} = \frac{4}{3}\pi \frac{Diameter^{3}}{4^{3}}\\\\ = \frac{4}{3}\pi \frac{Diameter^{3}}{4 * 4 * 4} = \frac{4}{3}\pi \frac{Diameter^{3}}{4 * 2 * 2 * 4} = \frac{4}{3}\pi \frac{Diameter^{3}}{8 * 8} = \frac{\frac{4}{3}\pi\frac{Diameter^{3}}{8}}{8}

But we can see that the numerator is exactly the original Volume!

This shows us that the Volume would be  \frac{1}{8} of the original Volume if the Diameter were reduced by half.

3 0
2 years ago
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