Which of these statements partly define law?
1 answer:
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Answer:
<h2>i. 9J and </h2><h2>ii. -9J</h2>Explanation:
Please see attached the diagram and also the FBD for your reference.
Step one:
given data
Weight w1=20N
Distance s1=75cm= 0.75m
Weight w2=12N
Distance s2=75cm =0.75m
Clearly, we are asked to find the work done by gravity and the tension in the string.
we know that work is defined as force times the distance traveled
W=F*D
and to know the force we need the acceleration, seeing that the system is stationary the acceleration due to gravity 9.81m/s^2 is not needed here
i . Work done by gravity = w2*s2=12*0.75=9J
ii. The tension is equal but opposite = -9J
1) 9.4 m/s
First of all, we can calculate the work done by the horizontal force, given by
W = Fd
where
F = 34.6 N is the magnitude of the force
d = 12.9 m is the displacement of the cart
Solving ,
W = (34.6 N)(12.9 m) = 446.3 J
According to the work-energy theorem, this is also equal to the kinetic energy gained by the cart:
Since the cart was initially at rest, , so
(1)
where
m is the of the cart
v is the final speed
The mass of the cart can be found starting from its weight, :
So solving eq.(1) for v, we find the final speed of the cart:
2)
The work done on the train is given by
W = Fd
where
F is the magnitude of the force
d is the displacement of the train
In this problem,
So the work done is
3)
According to the work-energy theorem, the change in kinetic energy of the train is equal to the work done on it:
where
W is the work done
is the change in kinetic energy
Therefore, the change in kinetic energy is
4) 37.2 m/s
According to the work-energy theorem,
where
is the final kinetic energy of the train
is the initial kinetic energy of the train, which is zero since the train started from rest
Re-writing the equation,
where
m = 36300 kg is the mass of the train
v is the final speed of the train
Solving for v, we find