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2 years ago

Why do meteors in a meteor shower appear to come from just one point in the sky?

Physics

1 answer:

kolbaska11 [484]2 years ago

4 0

Answer:

All the meteors in a meteor shower typically come from the same comet, which is in a periodic orbit around the Sun. The dust from the comet follows the path of the parent body and as Earth intersects the debris along the comet's orbit, it plows into this material. Since the dust particles are all moving together in space before they encounter Earth, if you trace back the streak of each meteor, its path will appear to diverge from one place in the sky.

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How many coulombs of charge do 50 * 10^31 electrons possess

Angelina_Jolie [31]

Quantity of Charge , Q = ne
Where n = number of electrons
e = charge on one electron = -1.6 * 10 ^-19 C.
n = 50 * 10^31 electrons

Q = (50 * 10^31)*( -1.6 * 10 ^-19 ) = -8 * 10^13 C.

Note that the minus sign indicates that the charge is a negative charge.

7 0

3 years ago

you are working in a physics lab where you have made a simple circuit with a battery and bulb in which part of your circuit is t

LiRa [457]

Answer:

The current moves in the terminal.

3 0

3 years ago

A pendulum of length L=36.1 cm and mass m=168 g is released from rest when the cord makes an angle of 65.4 degrees with the vert

pychu [463]

(a) -0.211 m

At the beginning the mass is displaced such that the length of the pendulum is L = 36.1 cm and the angle with the vertical is

$\theta=65.4^{\circ}$

The projection of the length of the pendulum along the vertical direction is

$L_y = L cos \theta = (36.1 cm)(cos 65.4^{\circ})=15.0 cm$

the full length of the pendulum when the mass is at the lowest position is

L = 36.1 cm

So the y-displacement of the mass is

$\Delta y = 15.0 cm - 36.1 cm = -21.1 cm = -0.211 m$

(b) 0.347 J

The work done by gravity is equal to the decrease in gravitational potential energy of the mass, which is equal to

$\Delta U = mg \Delta y$

where we have

m = 168 g = 0.168 kg is the mass of the pendulum

g = 9.8 m/s^2 is the acceleration due to gravity

$\Delta y = 0.211 m$ is the vertical displacement of the pendulum

So, the work done by gravity is

$W=(0.168 kg)(9.8 m/s^2)(0.211 m)=0.347 J$

And the sign is positive, since the force of gravity (downward) is in the same direction as the vertical displacement of the mass.

(c) Zero

The work done by a force is:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and the displacement

In this situation, the tension in the string always points in a radial direction (towards the pivot of the pendulum), while the displacement of the mass is tangential (it follows a circular trajectory): this means that the tension and the displacement are always perpendicular to each other, so in the formula

$\theta=90^{\circ}, cos \theta = 0$

and so the work done is zero.

5 0

2 years ago

What is the average speed of an object that travels 6 meters in 2 seconds and then travels 3 meters in 1 second?

olya-2409 [2.1K]

Answer:

3 m/s

Explanation:

Average Speed = $\frac{Total Distance}{Total time}$

Plug in the numbers, it will be (6m + 3m) divided by (2s + 1s), which is 9m/3s, which equals to 3m/s.

4 0

2 years ago

How do the conditions in tube c prevent air reaching the iron nail

lina2011 [118]

Answer:

The conditions stop air from getting to the nail is the oil

Explanation:

8 0

2 years ago