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Alina [70]
3 years ago
10

In the evening, the shadow of an object is very long due to the low position of the Sun. A 20m height lamp

Mathematics
1 answer:
jekas [21]3 years ago
7 0
58 I just took the test and got it right
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Help! can someone please give me the answer
AlladinOne [14]
<h2>I can't answer your question, but please mark it as brainliest</h2>

Pliss

7 0
3 years ago
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Can someone help me please
Vera_Pavlovna [14]

Answer:

B) Y = 5x - 10

Step-by-step explanation:

m = y2-y1 / x2-x1

Hope this helps. Pls give brainliest.

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3 years ago
A "point" is 1% of your borrowed amount on a mortgage. You want to pay 2 points to get a 0.5% reduction in your interest rate on
eduard
A point is 1% of your borrowed amount on a mortgage.
mortgage loan = 175,000

175,000 x 1% = 1,750 per point

1750 x 2 = 3,500 is the amount paid for the 2 points.
4 0
3 years ago
Find the domain of the following functions ?
jeka57 [31]

Answer:

A) x ≠ 0

B) x ≠ 3

Step-by-step explanation:

The domain is all the possible values of x such that f(x) exists.

A) f(x) = (x + 5) / x

x can't be 0 (can't divide by 0), so the domain of x is all values other than 0.

You can write this in interval notation:

(-∞, 0)⋃(0, ∞)

Inequality notation:

x < 0 or x > 0

Or simply:

x ≠ 0

B) f(x) = 1 / (x - 3)

x can't be 3 (can't divide by 0), so the domain of x is all values other than 3.

(-∞, 3)⋃(3, ∞)

x < 3 or x > 3

x ≠ 3

6 0
3 years ago
The output of an economic system​ Q, subject to two​ inputs, such as labor L and capital​ K, is often modeled by the​ Cobb-Dougl
Anna35 [415]

Answer:

Step-by-step explanation:

Given

Economic system Q is given by

Q=cL^aK^b

also a+b=1

if Q=12,200

a=\frac{1}{6}

b=\frac{5}{6}

c=42

substitute these values

12,200=42\times (L)^{\frac{1}{6}}K^{\frac{5}{6}}

(L)^{\frac{1}{6}}K^{\frac{5}{6}}=\frac{12,200}{42}

K^{\frac{5}{6}}=\frac{12,200}{42(L)^{\frac{1}{6}}}

K=(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^{5}}

differentiate w.r.t to L to get \frac{dK}{dL}

\frac{dK}{dL}=(\frac{12,200}{42})^{\frac{6}{5}}\times (-5)\times L^{-6}

\frac{dK}{dL}=-5(\frac{12,200}{42})^{\frac{6}{5}}\times \frac{1}{L^6}

\frac{dK}{dL}=-\frac{4515.466}{L^6}

6 0
3 years ago
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