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3 years ago

Which was a major effect of Pope Leo III crowning Charlemagne emperor of the Romans ?

Physics

1 answer:

Ivanshal [37]3 years ago

7 0

Answer:

The crowning of Charlemagne by Pope Leo III was significant in a number of ways. For Charlemagne, it was necessary because it encouraged to give him higher reliability. It gave him the rank of a dictator, giving him the only ruler in Europe west of the Byzantine emperor in Constantinople.

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Pls help will mark brain

BartSMP [9]

Answer: 100 units

Explanation:

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3 years ago

A man jumps horizontally from the top of a building that is 20.0m high, and hopes to reach a swimming pool that is at the bottom

Oliga [24]

Answer:

5 m/s

Explanation:

Given that the hight of the building, h= 20.0 m

The horizontal distance of the swimming pool from the building, d=10 m

As the man jumps horizontally, so the vertical velocity at the time of jumping is 0.

Let s be the initial horizontal velocity of the man at the time of jumping.

As the gravitational force always acts in the vertical direction, so, it does not change the horizontal speed.

So, the horizontal velocity, s, remains constant throughout the motion.

If t be the time of flight, then $s=10/t \cdots(i)$

Now, applying the equation of motion in the vertical direction,

$s=ut+\frac 1 2 at^2$

where u is the initial velocity, t is the time of flight, a is the acceleration, s is the displacement.

Here, putting s= 20 m, u=0, $a=g=9.81 m/s^2$ in the equation of motion, we have

$20=0\timest+\frac 1 2 (9.81)t^2 \\\\\Rightarrow 20 = \frac 1 2 (9.81)t^2 \\\\\Rightarrow t^2 = (20\times2)/9.81 \\\\$

$\Rightarrow t = 2$ seconds (approx)

Now, put t=2 in the equation ( we have

$s=10/2=5$ m/s

Hence, the man must jump with 5 m/s horizontally to reach the pool.

6 0

3 years ago

To have more resources in the future. We must ______ resources today.

GenaCL600 [577]

1. is the answer to this question

6 0

4 years ago

Read 2 more answers

What is the diameter of a 12lb shot if the specific gravity is of the shot iron in the shot is 6.8, the density of fresh water 6

marysya [2.9K]

Answer:

The diameter is 0.378 ft.

Explanation:

Given that,

Mass of shot = 12 lb

Density of fresh water = 62.4 lb/ft

Specific gravity = 6.8

We need to calculate the volume of shot

$V = \dfrac{4}{3}\pi r^3\ ft^3$

The density of shot is

Using formula of density

$\rho = \dfrac{m}{V}$

Put the value into the formula

$\rho =\dfrac{12}{ \dfrac{4}{3}\pi r^3}$

We need to calculate the radius

Using formula of specific gravity

$specific\ gravity =\dfrac{density\ of\ shot}{dnsity\ of\ water}$

Put the value into the formula

$6.8=\dfrac{\dfrac{12}{\dfrac{4}{3}\pi r^3}}{62.4}$

$r^3=\dfrac{12}{\dfrac{4}{3}\pi\times6.8\times62.4}$

$r^3=0.0067514$

$r =(0.0067514)^{\frac{1}{3}}$

$r=0.1890\ ft$

The diameter will be

$d = 2\times r$

$d =2\times0.1890$

$d =0.378\ ft$

Hence, The diameter is 0.378 ft.

7 0

3 years ago

A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, wha

Alborosie

Answer:

$v = 70.95 \ m/s.$

Explanation:

Given data:

Mass of the man, $m = 59 \ kg$

Total mechanical energy, $E_{i} = 150,023 \ \rm J$

Height, $h = 2.6 \ m$

Suppose there is no external force acting on the man. In this situation, the total mechanical energy (kinetic + potential) will remain steady.

Let the speed of the man at 2.6 m be <em>v</em>.

Thus,

$E_{i} = E_{f}$

$E_{i} = \frac{1}{2}mv^{2} + mgh$

$150023 = 0.5 \times 59 \times v^{2} + 59 \times 9.80 \times 2.6$

$\Rightarrow \ v = 70.95 \ m/s.$

6 0

3 years ago