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3 years ago

Find the factor of the number 1.30

Mathematics

1 answer:

Kazeer [188]3 years ago

8 0

Answer:

1,2,3,5,6,10,15,30

Step-by-step explanation:

Factors of 30 are the following:-

1x30=30

2x15=30

3x10=30

5x6=30

6x5=30

10x3=30

15x2=30

30x1=30

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3 years ago

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

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3 years ago

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Anna [14]

Answer:

y=x/2

Step-by-step explanation:

If one line is perpendicular to another, then the product of their slope is -1.

y = –2x+8. This line has a slope of -2. Which means another line must have a slope of 1/2.

By knowing the slope, we then assume this line as x-2y=k. Insert the point in, we find out k=0.

So the equation of this line is x-2y=0, or y=x/2.

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3 years ago

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DENIUS [597]

Answer:

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Step-by-step explanation:

Surface area of prism

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3 years ago

Find the factor of the number 1.30​

Find the factor of the number 1.30