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devlian [24]
3 years ago
10

Find the factor of the number 1.30​

Mathematics
1 answer:
Kazeer [188]3 years ago
8 0

Answer:

1,2,3,5,6,10,15,30

Step-by-step explanation:

Factors of 30 are the following:-

1x30=30

2x15=30

3x10=30

5x6=30

6x5=30

10x3=30

15x2=30

30x1=30

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Finger [1]

We have 2 angles that are supplementary, so their sum equals 180⁰.

(4x - 10) + (7x - 8) =180

11x - 18 = 180

11x = 198

x = 18

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Divide using long division. State the​ quotient, q(x), and the​ remainder, r(x).
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What are u supposed to be dividing
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1 year ago
Here we will study the function f (x) = e ^ x sin (x), where x ∈ [0, 2π]. a) Determine where the function is decreasing and incr
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fff

f(x) = e^x sin (x)

To find increasing and decreasing intervals we take derivative

f'(x) = e^xsin(x)+e^x(cosx)= e^x(sinx+cosx)

Now we set the derivative =0  and solve for x

e^x(sinx+cosx)=0

sinx + cosx =0

divide whole equation by cos x

\frac{sinx}{cosx} + \frac{cosx}{cosx} =0

tanx +1 =0

tanx = 1

x=\frac{3\pi }{4} and  x=\frac{7\pi}{4}

Now we pick a number between 0 to  \frac{3\pi }{4}

Lets pick  \frac{\pi }{2}

Plug it into the derivative

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Now we pick a number between   \frac{7\pi}{4} to 2pi

Lets pick  \frac{11\pi}{6}

Plug it into the derivative

f'(x) =e^{\frac{11\pi}{6}}(sin(\frac{11\pi}{6})+cos(\frac{11\pi }{6}))

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So the graph of f(x) is increasing on the interval (\frac{7\pi }{4}, 2\pi)

Increasing interval is (0,\frac{3\pi }{4}) U (\frac{7\pi }{4}, 2\pi)

Decreasing interval is (\frac{3\pi}{4}, \frac{7\pi}{4})

(b)

The graph of f(x) increases and reaches a local maximum at x=\frac{3\pi}{4}

The graph of f(x) decreases and reaches a local minimum at x=\frac{7\pi}{4}

(c)

f(0) = 0

f(2\pi)=0

f(\frac{3\pi }{4})=7.46

f(\frac{7\pi}{4})=-172.64

Here global maximum at x=\frac{3\pi}{4}

Here global minimum at x=\frac{7\pi}{4}


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saveliy_v [14]

Answer:

7) \dfrac{25c^2}{d^4}

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7)

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Answer:

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