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kenny6666 [7]
3 years ago
7

;)..........................................................................................

Chemistry
2 answers:
kotykmax [81]3 years ago
7 0

Answer:

;)..........................................................................................

Explanation:

Gre4nikov [31]3 years ago
4 0

Answer:

;)..........................................................................................

Explanation:

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However, compared to the other options, lead is too
fenix001 [56]

Answer:

dangerous and heavy

Explanation:

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Veseljchak [2.6K]

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Wat is significant figures
Sav [38]

<em>Answer:</em>

  •                   0.052301 km have 5 significant figure
  •                   400 cm have 1 significant figure
  •                   50.0 m  have 3 significant figure
  •                  4500.01 ml have 6 significant figure

<em>Explanation:</em>

According to rules of significant figure

0.052301 km have 5 significant figure:

  • Zero to the left of the first non zero digit not significant.
  • Zero between the non zero digits are significant.

<em>400 cm have 1 significant figure:</em>

  • Trailing zeros are not significant in numbers without decimal points.

<em>50.0 m  have 3 significant figure:</em>

  • Trailing zeros are significant in numbers when there is decimal points.

<em>4500.01 ml have 6 significant figure:</em>

  • Zero between the non zero digits are significant.
4 0
4 years ago
How many protons and electrons are present in a Ca2+ ion?
o-na [289]

Answer:

Ca2+ represents an ion with 20 protons and 18 electrons.

Explanation:

7 0
3 years ago
The specific heats and densities of several materials are given below: Material Specific Heat (cal/g·°C) Density (g/cm3) Brick 0
abruzzese [7]

<u>Answer:</u> The change in temperature is 84.7°C

<u>Explanation:</u>

To calculate the change in temperature, we use the equation:

q=mc\Delta T

where,

q = heat absorbed = 1 kCal = 1000 Cal    (Conversion factor: 1 kCal = 1000 Cal)

m = mass of steel = 100 g

c = specific heat capacity of steel = 0.118 Cal/g.°C

\Delta T = change in temperature = ?

Putting values in above equation, we get:

1000cal=100g\times 0.118cal/g^oC\times \Delta T\\\\\Delta T=\frac{1000cal}{100g\times 0.118cal/g^oC}\\\\\Delta T=84.7^oC

Hence, the change in temperature is 84.7°C

5 0
3 years ago
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