Explanation:
We have given the acid that is, acetic acid. It is known that acetic acid is a weak acid.
Therefore, formula that depicts relationship between pH,
and weak acid is as follows.
pH =
+ log![\frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
where, [HA] = concentration of weak acid
= concentration of conjugate base of given weak acid
Since, we have to calculate the concentration of conjugate base of acetic acid. So, let it be equal to x. Whereas concentration of acetic acid is 10 mmol,
is 4.74 and pH is 5.03.
Hence, putting these values in the above formula as follows.
pH =
+ log![\frac{[A^{-}]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E%7B-%7D%5D%7D%7B%5BHA%5D%7D)
5.03 = 4.74 + log
= antilog (0.29)
x = 19.4 mmol
Thus, we can conclude that there is 19.4 mmol acetate (the conjugate base of acetic acid) will be needed to add to this given solution.
Answer:
Solution that is 0.100 M CH3COOH (acetic acid)
and 0.100 M NaCH3COO (sodium acetate)
Find pH of buffer solution:
CH3COOH(aq) + H2O ↔ CH3COO-
(aq) + H3O+(aq)
[CH3COOH] [CH3COO-
] [H3O+]
initial 0.100 0.100 ≈0
-x x x
equil 0.100 – x 0.100 + x xFind pH of buffer solution:
CH3COOH(aq) + H2O ↔ CH3COO-
(aq) + H3O+(aq)
Ka = [CH3COO-
][H3O+
]
[CH 3COOH] = (.100 + x)x
(.100 - x) = 1.8 x 10-5
x = 1.80 x 10-5 M
pH = 4.7
Explanation:
The answer I believe would be A
Answer: C) the rate of forward reaction is not equal to the rate of backward reaction. This should be the answer.
Explanation: