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yan [13]
3 years ago
15

Find errors in this equation. Ca(s) + water(l) -> C(OH)2 (aq) + H(6)

Chemistry
1 answer:
vladimir1956 [14]3 years ago
4 0
Calcium (s) + h2o (i) -> carbon(oh)2 (AQ) +h(6)
well aq isnt a element.  
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Examples of a pure substances
DiKsa [7]

Answer:

Explanation:

Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements.

3 0
2 years ago
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A carboxylic acid is named in the IUPAC system by replacing the -e in the name of the parent alkane with
serg [7]

A carboxylic acid is named in the IUPAC system by replacing the -e in the name of the parent alkane with -<u>oic acid</u>

<u></u>

<h3>What is carboxylic acid?</h3>

Carboxylic acid is an organic acid that contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO2H, with R referring to the alkyl, alkenyl, aryl, or other group. Carboxylic acids occur widely. Important examples include the amino acids and fatty acids. Deprotonation of a carboxylic acid gives a carboxylate anion.

Carboxylic acids are commonly identified by their trivial names. They often have the suffix -ic acid. IUPAC-recommended names also exist; in this system, carboxylic acids have an -oic acid suffix. For example, butyric acid (C3H7CO2H) is butanoic acid by IUPAC guidelines. For nomenclature of complex molecules containing a carboxylic acid, the carboxyl can be considered position one of the parent chain even if there are other substituents, such as 3-chloropropanoic acid. Alternately, it can be named as a "carboxy" or "carboxylic acid" substituent on another parent structure, such as 2-carboxyfuran.

Learn more about carboxylic acid

brainly.com/question/26855500

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5 0
1 year ago
Rod cells work best in dim light and enable you to see black, white, and shades of gray.
Ivenika [448]
Answer:
True rod cell are best in the dark or dim light.
7 0
3 years ago
Consider four elements from Group 7A: fluorine in the second period, chlorine in the third period, bromine in the fourth period,
madam [21]
Onization energy is the energy required to lose an electron and form an ion. The stronger is the attraction of the atom and the electron the higher the ionization energy, and the weaker is the attraction of the atom and the electron the higher the ionization energy. This leads to a clear trend in the periodic table. Given that the larger the atom the weaker the attraction of the atom to the valence electrons, the easier they will be released, and the lower the ionization energy. This is, as you go downward in a group, the ionization energy decreases. So, the element at the top of the group will exhibit the largest ionization energy. <span>Therefore, the answer is that of the four elements of group 7A, fluorine will have the largest first ionization energy.</span>
7 0
3 years ago
Read 2 more answers
At 500 degree C, F_2 gas is stable and does not dissociate, but at 840 degree C, some dissociation occurs: F_2 (g) 2 F(g). A fla
bazaltina [42]

Answer:

2.73 is the equilibrium constant for the dissociation of F_2 gas at 840 degree Celsius.

Explanation:

F_2(g)\rightleftharpoons 2F(g)

Initial

0.600 atm    0

Equilibrium

(0.600 atm - p)        2p

Total pressure at equilibrium = P = 0.984 atm

P= 0.600 atm - p)+2p=0.984 atm

p = 0.384 atm

Partial pressure of the F_2 gas , p_{f_2}= (0.600 atm - 0.384 atm)=0.216 atm

Partial pressure of the F gas, p_{f} = 2(0.384 atm)=0.768 atm

K_p=\frac{(p_{F})^2}{p_{F_2}}

K_p=\frac{(0.768 atm)^2}{0.216 atm}=2.73

2.73 is the equilibrium constant for the dissociation of F_2 gas at 840 degree Celsius.

7 0
3 years ago
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