The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg
<h3>Data obtained from the question</h3>
- Year 1800 percent = 0.028%
- Year 2013 percent = 0.040%
- Mass of air = 500 Kg
- Difference =?
<h3>How to determine the mass of CO₂ in 500 Kg in year 1800</h3>
- Year 1800 percent = 0.028%
- Mass of air = 500 Kg
- Mass of CO₂ =?
Mass = percent × mass of air
Mass of CO₂ = 0.028% × 500
Mass of CO₂ = 0.14 Kg
<h3>How to determine the mass of CO₂ in 500 Kg in year 2013</h3>
- Year 1800 percent = 0.040%
- Mass of air = 500 Kg
- Mass of CO₂ =?
Mass = percent × mass of air
Mass of CO₂ = 0.040% × 500
Mass of CO₂ = 0.2 Kg
<h3>How to determine the difference</h3>
- Mass of CO₂ in year 1800 = 0.14 Kg
- Mass of CO₂ in year 2013 = 0.2 Kg
- Difference =?
Difference = mass in 2013 - mass in 1800
Difference = 0.2 - 0.14
Difference = 0.06 Kg
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Answer:
194 kg m²
Explanation:
Use parallel axis theorem:
I = I₀ + mr²
I = 25 kg m² + (1 kg) ((5 m)² + (12 m)²)
I = 25 kg m² + 169 kg m²
I = 194 kg m²
Vector is perpendicular to x axis or i component.
Hence i component is 0
j component is 63.5
Answer:
Option d) can not be determined from the given information
Explanation:
Water is a polar molecule consisting of 2 positive hydrogen atoms and a negative oxygen atom.
When a stream of water is deflected by positively charged object, the water molecules are oriented in such a way that oxygen in water, being negatively charge gets attracted to the charged object and aligns near the object whereas hydrogen aligns on the opposite side overcoming the inter-atomic repulsion.
Similar is the case with hydrogen in case the object is negatively charged.
Therefore, it explains that water is a polar molecule and gets attracted to both positive and negative charges and hence, the sign of the object can not be determined.
• 1st Making an observation •2nd Starting a question •3rd Formulating a hypothesis • 4th Conducting an experiment, then... • Finally, Analyzing the data & writing down/drawing conclusions
