Answer:
(b) Water
Explanation:
The density of the liquid is found by dividing its mass by its volume.
__
<h3>mass</h3>
The mass of the liquid is the difference in mass between the full and empty graduated cylinder:
liquid mass = (145 g) -(45 g) = 100 g
<h3>volume</h3>
The cylinder is said to contain 100 mL of the liquid, so that is the volume of interest.
<h3>density</h3>
The ratio of mass to volume is the liquid's density:
ρ = (100 g)/(100 mL) = 1 g/mL
This density identifies the most likely liquid as water.
Answer: 2.13 × 10^-4 A
Explanation:
Given that the RLC circuit has a resistance R = 200 Ω and an inductance L = 15 mH.
Its oscillation frequency F = 7000 Hz
The initial current I = 25 mA = 25/1000 or 25 × 10^-3 A
Since there is no charge on the capacitor, the current after complete 5 circle will be achieved by using the formula in the attached file.
Please find the attached file for the remaining explanation for the solution.
Answer:
the jumper's speed just as he leaves the ground = 4.2 m/s
the force he must exert on the ground to perform the 0.90 m jump = 4.99 × 10³ N
Explanation:
Given that :
height h = 0.90 m
mass = 51 kg
distance s = 0.10 m
What is the jumper's speed just as he leaves the ground?
The velocity P.E = K.E
where;
g = 9.8
v = 4.2 m/s
the jumper's speed just as he leaves the ground = 4.2 m/s
What force must he exert on the ground to perform the 0.90 m jump?
Let's first determine the acceleration by using the equation of motion;
v² = u² + 2as
4.2² = 0 + 2(a)(0.10)
17.64 = 0.2 a
a = 17.64/0.2
a = 88.2 m/s²
The force F is now calculated by the relation:
F - mg = ma
F = mg+ ma
F = m(g+a)
F = 51(9.8 + 88.2)
F = 4988 N
F = 4.99 × 10³ N
Answer : Option D) 90°N and 90°S
Explanation : The latitudes which are given in the options are the angle to be measured in the direction of north and south respectively taking equator as the central line.
When it is 90°N and 90°S it means it forms an right angle and faces towards north and south respectively with respect to the equator, so there are high chances of pointing towards the Arctic and Antarctic regions respectively; therefore giving greater probability of finding glaciers.