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Ber [7]
3 years ago
13

En el mar, la luz visible alcanza una profundidad de aproximadamente 200 metros (zona fotica). ¿De dónde obtienen energías las p

lantas y los animales por debajo de esa profundidad?
Physics
1 answer:
Marizza181 [45]3 years ago
3 0

Answer:

Explanation:

En la zona apótica (profundidad inferior a 200 m); todo lo que queda de la luz solar es una luz tenue, opaca, azul-verde, demasiado impotente para siquiera considerar permitir que ocurra la fotosíntesis. Sin embargo, hay comida para tener; basura, trozos de plantas podridas y derroche de criaturas caen desde arriba para cuidar a los seres vivos en la zona apótica.

Las formas de vida a una profundidad inferior a 200 m dependen de los productos químicos que salen de los respiraderos; el procedimiento que utilizan para hacer los alimentos se llama quimiosíntesis en lugar de fotosíntesis.

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An elevator has a mass of 3000 kg. If the upward tension in the
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Answer: 18 m

Explanation: because it does

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3 years ago
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A coil of wire with 50 turns lies in the plane of the page and has an initial area of 0.140 m2. The coil is now stretched to hav
DENIUS [597]

Answer:

Magnitude of induced emf will be 87.5 volt

Direction of induced emf will be clockwise  

Explanation:

We have given number of turns in the coil N = 50

Initial area A=0.140m^2

Time is given dt = 0.1 sec

Magnetic field B = 1.25 T

From Faraday's law of electromagnetic induction

ne=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

e=-50\times 0.140\times \frac{1.25}{0.1}=-87.5volt

So magnitude of induced emf is 87.5 volt

Direction of induced emf will be clockwise

7 0
4 years ago
A spring with a spring constant of 4 N/m is stretched by Sarah's dog until extended by 2 m. How much elastic potential energy is
azamat

Hi there!

Recall the equation for spring potential energy:

PE = \frac{1}{2}kx^2

k = Spring constant (N/m)

x = extension of spring from equilibrium (m)

PE = Potential Energy (J)

Plug in the given values:

PE = \frac{1}{2}(4)(2^2) = \boxed{8 J}

8 0
2 years ago
The electric current in a wire is 1.5A. How many electrons flow past a given point in a time of 2s?
kipiarov [429]

Answer:

The amount of electrons that flow in the given time is 3.0 C.

Explanation:

An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.

i.e           I = \frac{Q}{t} ...................(1)

It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.

In the given question, I = 1.5A, t = 2s, find Q.

From equation 1,

            Q = I × t

                = 1.5 × 2

               = 3.0 Coulombs

The amount of electrons that flow in the given time is 3.0 C.

5 0
3 years ago
At the end of the adiabatic expansion, the gas fills a new volume V₁, where V₁ > V₀. Find W, the work done by the gas on the
tino4ka555 [31]

Answer:

W=\frac{p_0V_0-p_1V_1}{\gamma-1}

Explanation:

An adiabatic process refers to one where there is no exchange of heat.

The equation of state of an adiabatic process is given by,

pV^{\gamma}=k

where,

p = pressure

V = volume

\gamma=\frac{C_p}{C_V}

k = constant

Therefore, work done by the gas during expansion is,

W=\int\limits^{V_1}_{V_0} {p} \, dV

=k\int\limits^{V_1}_{V_0} {V^{-\gamma}} \, dV

=\frac{k}{\gamma -1} (V_0^{1-\gamma}-V_1^{1-\gamma})\\

(using pV^{\gamma}=k )

=\frac{p_0V_0-p_1V_1}{\gamma-1}

4 0
3 years ago
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