Evaporation (or another word to use is water vapor.)
The velocity is given by:
V = √(Vx²+Vy²)
V = velocity, Vx = horizontal velocity, Vy = vertical velocity
Given values:
Vx = 6m/s, Vy = 12m/s
Plug in and solve for V:
V = √(6²+12²)
V = 13.42m/s
Now find the direction:
θ = tan⁻¹(Vy/Vx)
θ = angle of velocity off horizontal, Vy = vertical velocity, Vx = horizontal velocity
Given values:
Vx = 6m/s, Vy = 12m/s
Plug in and solve for θ:
θ = tan⁻¹(12/6)
θ = 63.4°
The resultant velocity is 13.42m/s at an angle of 63.4° off the horizontal.
There's no air in space, so there's no air resistance there.
The distance covered by the acorn is 3.136 m.
<u>Explanation:</u>
The time taken for the acorn to hit the ground is 0.8 s. As it is a free fall, the acorn will be completely under the influence of gravity. So the acceleration will be acceleration due to gravity.
Then using the second law of equation,
![s=ut+\frac{1}{2}gt^{2}](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dgt%5E%7B2%7D)
Since the initial velocity and time is zero, then the time taken to reach the ground is stated as 0.8 s, so
![s=0+\left(\frac{1}{2} \times 9.8 \times 0.8 \times 0.8\right)=\frac{6.272}{2}=3.136 \mathrm{m}](https://tex.z-dn.net/?f=s%3D0%2B%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%209.8%20%5Ctimes%200.8%20%5Ctimes%200.8%5Cright%29%3D%5Cfrac%7B6.272%7D%7B2%7D%3D3.136%20%5Cmathrm%7Bm%7D)
So the distance covered by the acorn is 3.136 m.