Answer:
0.2916, 0.1488, 0.0319
Step-by-step explanation:
Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.
Since each trial is independent there is a constant probability for any random car to need oil is 0.10
Let X be the number of cars that need oil
A) Here X is BIN(4,0.1)

B) Here X is Bin (8, 0.1)

C) Here X is Bin (20,5)

Answer:
14 % you just gotta count the green boxes and make it a percentage