Answer:
775 grams of ice
Explanation:
Heat loss by patient = heat gained by ice
Heat loss by patient = mass×specific heat capacity×(initial temperature - final temperature) = 62×4200×(40-39) = 260,400J
Heat gained by ice = mass × specific latent heat of fusion of ice = m×336000 = 336000m J
336000m = 260,400
m = 260400/336000 = 0.775kg = 0.775×1000 grams = 775 grams of ice
Answer:
t = 6.15 minutes
α = - 3.9 x 10^-3 rad/s^2
Explanation:
n = 42.3 rev
angle turns in one revolution = 2 π radians
Angle turns in 42.3 rev = 2 x 3.14 x 42.3 = 265.644 rad
ωo = 1.44 rad/s, ω = 0
Let t be the time taken to stop and the angular acceleration is α.
Use third equation of motion for rotational motion
ω^2 = ωo^2 + 2 α θ
0 = 1.44 x 1.44 + 2 α x 265.644
α = - 3.9 x 10^-3 rad/s^2
Use first equation of motion for rotational motion
ω = ωo + α t
0 = 1.44 - 3.9 x 10^-3 x t
t = 368.95 second = 6.15 minutes
Let's take the initial mass of the object = m
velocity = v
initial KE = 1/2 mv² = 0.5mv²
Now the velocity is trippled
V = 3v
mass is cut in half
M = 0.5m
final KE = 1/2 MV² = 1/2 x (0.5m) x (3v)² =9/4 mv² = 2.25 mv²
Change in KE = 2.25mv² - 0.5mv² = 1.75mv²
% change = (Change in KE/initial KE) x 100
= (1.25mv²/0.5mv²) x 100
= (1.25/0.5) x 100
=250%
Change in kinetic energy is 250%
Hope it helps!
We need a and we have m and F . Now a = f÷m so therefore a = 4,9 ÷ 0,5 which is 0,98 metres per cubic second
Answer:
give me a minute to find the answer
Explanation:
