Recall that
![{v_f}^2-{v_i}^2=2a\Delta x](https://tex.z-dn.net/?f=%7Bv_f%7D%5E2-%7Bv_i%7D%5E2%3D2a%5CDelta%20x)
where
and
are the initial and final velocities, respecitvely;
is the acceleration; and
is the change in position.
So we have
![\left(21\dfrac{\rm m}{\rm s}\right)^2-{v_i}^2=2\left(0.853\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)](https://tex.z-dn.net/?f=%5Cleft%2821%5Cdfrac%7B%5Crm%20m%7D%7B%5Crm%20s%7D%5Cright%29%5E2-%7Bv_i%7D%5E2%3D2%5Cleft%280.853%5Cdfrac%7B%5Crm%20m%7D%7B%5Cmathrm%20s%5E2%7D%5Cright%29%28120%5C%2C%5Cmathrm%20m%29)
![\implies v_i\approx\boxed{15.4\dfrac{\rm m}{\rm s}}](https://tex.z-dn.net/?f=%5Cimplies%20v_i%5Capprox%5Cboxed%7B15.4%5Cdfrac%7B%5Crm%20m%7D%7B%5Crm%20s%7D%7D)
(Normally, this equation has two solutions, but we omit the negative one because the car is moving in one direction.)
<span>A complete path through which charge can flow is an "Electric Circuit"
Hope this helps!</span>
Answer:
85.556metres
Explanation:
Using pythagorean theorem
C²=A²+B²
we have c as the hypotenuse vector A thus:
93.8²=A²+38.4²
93.8²-38.4²=A²
8794.44-1474.56=A²
7319.88=A²
A=85.556
Answer:
0m/s
Explanation:
Since its fired at an angle, at the top there will be a split second where the velocity will be 0, as it has a parabolic shape, so the speed at the top of its path is 0