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sergejj [24]
3 years ago
5

g A small car travels up the hill with a speed of v = 0.2 s (m/s) where s is the distance measured from point A in meters. Deter

mine the magnitude of the car’s acceleration when it reaches s = 50 (m) where the road’s radius of curvature is r
Physics
1 answer:
jasenka [17]3 years ago
5 0

Answer:

The magnitude of the acceleration of the car when s = 50\,m is 2\,\frac{m}{s^{2}}.

Explanation:

The acceleration can be obtained by using the following differential equation:

a = v \cdot \frac{dv}{ds}

Where a, v and s are the acceleration, speed and distance masured in meters per square second, meters per second and meters, respectively.

Given that v = 0.2\cdot s, its first derivative is:

\frac{dv}{ds} = 0.2

The following expression is obtained by replacing each term:

a = 0.2\cdot 0.2\cdot s

a = 0.04\cdot s

The magnitude of the acceleration of the car when s = 50\,m is:

a = 0.04\cdot (50\,m)

a = 2\,\frac{m}{s^{2}}

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