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mrs_skeptik [129]
3 years ago
12

A thin metallic spherical shell of radius 0.357 m has a total charge of 5.03 times 10^-6 C placed on it. At the center of the sh

ell is placed a point charge of 4.15 times 10^-6 C. what is the electric field at a distance of 0.815 m from the center of the spherical shell? Gauss's law states that the total electric flux contained in an enclosed area (in this case, a shell of radius 0.815m from the center of the point charge) is proportional to the total charge within the enclosed area. Thus, the electric field at the point of interest is the sum of the electric field due to the point charge and the electric field of the distributed charge treated as a point charge located at the center of the spherical shell.
Physics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer:

The electric field is 5.623\times10^{4}\ N/C

Explanation:

Given that,

Radius = 0.357 m

Charge Q=5.03\times10^{-6}\ C

Point charge q=4.15\times10^{-6}\ C

Distance = 0.815 m

We need to calculate the total electric field

Using formula of electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q}{r^2}

Where, q = point charge

r = distance

Put the value into the formula

E=\dfrac{9\times10^{9}\times4.15\times10^{-6}}{(0.815)^2}

E=5.623\times10^{4}\ N/C

Hence, The electric field is 5.623\times10^{4}\ N/C

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You are holding a finishing sander with your right hand. THe sander has a flywheel which spins counterclockwise as seen from beh
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Answer:

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From the information given:

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3 years ago
Please help, and show steps. Thank you very much!
Vikentia [17]
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t = ?
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A concave spherical mirror has a radius of curvature of magnitude 20.0 cm. (a) Find the location of the image for object distanc
Tems11 [23]

Answer:

Answered

Explanation:

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then the focal length f = R/2 = 10 cm

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7 0
3 years ago
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