All categories

3 years ago

Need help with this physics question!

Physics

1 answer:

Fynjy0 [20]3 years ago

6 0

Answer:

omg i need help with the same answer lol

Explanation:

i wish i can help but i need help on this hehe

You might be interested in

(this is somehow part of my science unit, dont ask why)

nirvana33 [79]

Answer:

Height of coffee mug = 5 cm

Explanation:

Changing all the data given in to unit cm

50 mm = 5 cm

20 cm = 20 cm

8 m = 800 cm

0.1 km = 100 m = 10000 cm

Since we need to find the height of coffee mug, it's height will not be more than 10 cm.

So 5 cm is the correct choice.

6 0

4 years ago

An elevator cab is pulled directly upward by a single cable. The elevator cab and its single occupant have a mass of 2300 kg. Wh

Murrr4er [49]

Answer:

15.64 KN

Explanation:

mass of the elevator cab with a single occupant= 2300 kg

acceleration relative to the cab $a_{ce}$ = 6.80 m/s^2

acceleration of the coin relative to the cab in the opposite direction of motion of cab so we can consider it as a= -6.80 m/s^2

The acceleration of elevator cab relative to the ground $a_{cg}$

now we can say that

$a_{ce} +a_{eg} =a_{cg}$

=-6.80+ a_{eg}= -9.8

[tex]a_{eg}=-9.8+6.80=-3.8

The forces that act on elevator cab are tension and gravitational, applying newtons second law

T- mg= ma_{eg}

Then the tension in the cable is

T= 2300(-3.8)+2300×9.8= 15640 N= 15.64 KN

therefore tension in the string will be 15.64 KN

3 0

3 years ago

Often called velocity this is the velocity of an object at a particular moment in time

Yuliya22 [10]

Instantaneous speed?

8 0

3 years ago

Now the king had a grand-vizir who was avaricious, and envious, and a very bad man. He grew extremely jealous of the physician,

BlackZzzverrR [31]

<h2><em>He wants the king’s complete attention. </em></h2><h2><em> </em></h2><h2><em>He is afraid of someone pointing out the error of his false accusations. </em></h2><h2><em> </em></h2>

6 0

3 years ago

An anchor with a density of 700 lb/ft3 tied to a rope is submerged in water (but is not touching the bottom). It has a volume of

Ivanshal [37]

Answer:

Explanation:

Given

Density of anchor $\rho _a=700\ lb/ft^3$

Volume of anchor $V=2.8\ ft^3$

Density of water $\rho _w=62.4\ lb\ft^3$

Buoyancy force on submerged object is given by

$F_B=\rho _W\times V\times g$

$F_B=62.4\times 2.8\times 32.2=5625.98\approx 5626\ approx lbf$

3 0

3 years ago