Acetylene (C2H2) contains a triple bond
Answer:
The answer to your question is 4.14 g of O₃
Explanation:
Data
mass of nitrogen dioxide = 3.97 g
mass of ozone = x g
Reaction
NO₂ (g) + O₂ (g) ⇒ NO (g) + O₃ (g)
- Check that that reaction is balanced
Reactants Elements Products
1 N 1
4 O 4
This reaction is balanced
- Calculate the molecular mass of NO₂ and O₃
NO₂ = 14 + 32 = 46 g
O₃ = 48 g
- Calculate the mass of Ozone formed.
46 g of NO₂ ------------------ 48 g of O₃
3.97 gof NO₂ ---------------- x
x = (3.97 x 48 ) / 46
x = 190.56 / 46
x = 4.14 g of O₃
7 different types of tide
The number of sulfate ions that are in 100 ml of a solution of 0.0020 M Fe2(SO4)3 is 6 x10 ^-4 moles
calculation
find the moles of Fe2(SO4)3 that dissociated
moles = molarity x volume in liters
volume in liters = 100/1000 = 0.1 liters
molarity =0.002 M
moles = 0.002 x0.1 =2 x10 ^-4 moles
write the equation for dissociation
Fe2(SO4)3 = 2fe^3+ + 3 SO4^2-
by use of mole ratio between Fe2(SO4)3 to SO4^2- which is 1:3 therefore the moles of SO4^2- is
= 0.0002 x3 = 6 x10 ^-4 moles