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Sunny_sXe [5.5K]
3 years ago
8

Which of the following are car safety features that rely on increasing the

Physics
1 answer:
zubka84 [21]3 years ago
6 0
All of the above because crumple zones and seatbelts and airbags do get ruined so all of the above
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If Abdul pedals his 20 kg bike with a force of 100 N, what will the bike’s acceleration be? The formulas above may be helpful in
Scorpion4ik [409]

Answer:

5 m/s/s

Explanation:

F = ma

100 = 20a

100/20 = a

a = 5 m/s/s

4 0
3 years ago
What is the momentum of a bird with a mass of 0.018kg flying at 15m/s?
Mazyrski [523]

Answer:

0.27 kg-m/s

Explanation:

i believe this is the correct answer

6 0
3 years ago
After 16.5 s, a jogger’s displacement is 200.0 m. What is her average velocity in m/s? In km/h?
vivado [14]

Answer:

12.12 m/s

Explanation:

3 0
3 years ago
A small drop of water is suspended motionless in air by a uniform electric field that is directed upward and has a magnitude of
Gennadij [26K]

To solve this problem we will apply the concepts related to the electric field such as the smelting of the Force and the load (In this case the force is equivalent to the weight). Later we will apply the ratio of the total charge as a function of the multiplication of the number of electrons and their individual charge.

E = \frac{mg}{q}

Here,

m = mass

g = Acceleration due to gravity

Rearranging to find the charge,

q = \frac{mg}{E}

Replacing,

q = \frac{(3.37*10^{-9})(9.8)}{11000}

q = 3.002*10^{-12}C

Since the field is acting upwards the charge on the drop should be negative to balance it in air. The equation to find the number of electrons then is

q = ne

Here,

n = Number of electrons

e = Charge of each electron

n = \frac{q}{e}

Replacing,

n = \frac{3.002*10^{-12}}{1.6*10^{-19}}

n = 2.44*10^7

Therefore the number of electrons that reside on the drop is 2.44*10^7

5 0
4 years ago
Two common terms for a decrease in velocity are
Colt1911 [192]

deceleration or rėtardation i’m pretty sure (it won’t let me say the second word but it’s correct)

6 0
4 years ago
Read 2 more answers
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